Recent content by Chestermiller

It gains potential energy if its elevation decreases since, under this situation, gravity does negative work on the body.

The simplest way to interpret this is to say that the change in potential energy is minus the work done by gravity on the body ##-mg\Delta h##: $$W+W_g=W-mg\Delta h=0$$or $$W=-W_g=mg\Delta h=\Delta PE$$where W is the work done on the body by the applied external force F.

Does neon behave as an ideal gas at this temperature and pressure?

All you need to do is to use the gas law. The Maxwell relation is unnecessary for this problem.

Oops. I assumed that v was equal to the gradient of phi rather than minus the gradient of phi. So just flip the signs in my previous post.

So, at large r, $$\frac{\partial\Phi}{\partial r}=V\cos{\theta}$$ and $$\frac{\partial \Phi}{\partial \theta}=-Vr\sin{\theta}$$

What are the components of the far-field velocity in spherical coordinates?

What are the velocity components far from the sphere?

Your derivation assumes that the pressure is uniform over the volume V. This is not correct.

Where was the temperature measured in the experiments? Was the placement of the thermocouple consistent in all 3 cases (i.e., the same distance above the bottom)? How do you know that the induction heating rate of the pots was the same in all the cases? Would placing all four pots on the same...

In the direction parallel to the plate movement.

In this case, you can use lubrication theory in which the plates are treated as "locally parallel", and in which. although over a period of the sinusoid, the pressure change is zero, the pressure varies locally axially, and there is a net axial flow (although it is not the value that would be...

Let ##dQ_H## be the differential increments of heat received by the engine during the heating part of the cycle, ##dQ_C## be the increments of heat rejected by the engine during the cooling part of the cycle, ##T_{max}## be the maximum temperature during the heating part of the cycle, and...

Yes. But as long as the sinusoidal length period. is very large compared to the height of the channel, the vertical components of velocity will be small.

The equation for the pressure gradient in the tube goes like: $$\frac{dP}{dz}=-\left(\frac{4}{D}\right)\left(\frac{1}{2}\rho v^2\right)\left(\frac{0.0791}{Re^{0.25}}\right)$$where we have assumed that the flow is turbulent and the Reynolds number lies in the range 2000 < Re < 100000. The term...