Does Poisson's ratio apply when we have no loadings?

  • #1
question4
2
0
Does Poisson's ratio apply when we have no loadings ? For instance if we have a free rod and we increase its temperature, in order to find the change of its diameter should i say :
Δd=-v*ε_x*d, where d is the length of the diameter or Δd= α*ΔΤ*d ?
Thanks in advance.
 
Engineering news on Phys.org
  • #2
question4 said:
Does Poisson's ratio apply when we have no loadings ? For instance if we have a free rod and we increase its temperature, in order to find the change of its diameter should i say :
Δd=-v*ε_x*d, where d is the length of the diameter or Δd= α*ΔΤ*d ?
Thanks in advance.
Poisson's Ratio is stress related. If you apply a stress in a given direction causing a strain, it quantifies what happens in lateral directions in terms of expansion/contraction for a given material.

Uniformly heating (i.e. changing the temp of) a free rod is stress free.
 
Last edited:
  • Like
Likes DeBangis21, Lnewqban and Chestermiller
  • #3
erobz said:
Poisson's Ratio is stress related. If you apply a stress in a given direction causing a strain, it quantifies what happens in lateral directions in terms of expansion/contraction for a given material.

Uniformly heating (changing the temp) a free rod is stress free.
So in order to find the change of the diameter is it enough to say that : Δd= α*ΔΤ*d ?
 
  • #4
question4 said:
So in order to find the change of the diameter is it enough to say that : Δd= α*ΔΤ*d ?
Well, I believe that formula is for ##\frac{\delta }{L} \ll 1##, but basically...yes.
 
  • Like
Likes question4
  • #5
Welcome, @question4 ! :cool:

In practice, the linear expansion of metals is the most calculated due to its negative consequences.
Diameters of solid metal bars also grow with temperature, but that is mainly important for rings that slide tightly into cavities (like a bearing in its housing).

The diametral expansion of those rings are calculated like an unfolded section of metal expanding linearly; therefore, a coefficient of linear expansion is mostly used.

For fluids, a coefficient of volumetric expansion is used instead.

Please, see:
https://pressbooks.bccampus.ca/collegephysics/chapter/thermal-expansion-of-solids-and-liquids/

https://www.engineeringtoolbox.com/volumetric-temperature-expansion-d_315.html

https://www.engineeringtoolbox.com/thin-circular-ring-radius-temperature-change-d_1612.html

https://www.engineeringtoolbox.com/linear-thermal-expansion-d_1379.html

Now, when combining mechanical loads and high temperatures:

Copied from
https://en.wikipedia.org/wiki/Poisson's_ratio

"Most steels and rigid polymers when used within their design limits (before yield) exhibit values of about 0.3, increasing to 0.5 for post-yield deformation which occurs largely at constant volume."

The forging process shown in this video seem to demonstrate that any ratio (determined experimentally for metal in normal conditions) would change depending on sufficiently high applied loads and/or temperatures to the molecular bonds.

 
Last edited:
  • #6
This video can be helpful:
 

Similar threads

  • Mechanical Engineering
Replies
7
Views
2K
Replies
15
Views
602
  • Engineering and Comp Sci Homework Help
Replies
5
Views
1K
  • Mechanical Engineering
Replies
21
Views
827
  • Mechanical Engineering
Replies
1
Views
2K
  • Mechanical Engineering
Replies
5
Views
3K
  • Mechanical Engineering
Replies
4
Views
2K
  • Introductory Physics Homework Help
Replies
6
Views
2K
  • Mechanical Engineering
Replies
5
Views
2K
  • Mechanical Engineering
Replies
4
Views
3K
Back
Top