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bluffreggie
Oct21-09, 09:00 AM
Hi all,

i am working through some worked examples for my course and there seems to be a step missing.

the step says

"the internal diameter of the vessel can be determined from"

V=PI*r^2*4r

Now all im given is that the volume V is 20 litres. is there any way i can determine the radius from this?

The answer written is r=0.117m

Thanks for any help guys!!

scottie_000
Oct21-09, 09:09 AM
Assuming the vessel is filled with water, do you know how many litres of water is in a cubic metre? Or how many ml makes up a cubic centimetre?
From there you need to be able to rearrange this equation to solve for r in terms of V

SinghTutorial
Oct21-09, 09:09 AM
if I say x^3 = 8, is it ok to say x = 2
This problem is just like the one above

V = PI * 4 * r^3

or r^3 = V / ( PI * 4)

so r = ( V / (PI * 4) )^(1/3)

Another this to remember is V is given in liters so you have to convert it into m^3.
20 liters = .02 m^3

and if you plug the above equation in a calculator, you get r = 0.11675m

hope it helps

scottie_000
Oct21-09, 09:13 AM
Or you could just answer the entire question....
Is it not better to give a few hints, so that the OP will understand how to do it themselves?

bluffreggie
Oct21-09, 09:25 AM
Ahh i forgot the like terms of the r^2 and r!!!!
i can not seem to get it to work on my calculator.
I get for (V/Pi*4)) = 0.02/Pi*4 = 1.59*10-3
How do i use ^(1/3)?
Is it the abc function?

scottie_000
Oct21-09, 09:35 AM
^(1/3) just means cube root, so is there a button with a 3 in a square root sign?

bluffreggie
Oct21-09, 09:39 AM
yeah got it just. thanks mate. That was just the front end of the question. the rest is straight forward just got hung up on the rearrangment side of it. i was close but not close enough!!!!

scottie_000
Oct21-09, 10:38 AM
Glad to help