arivero

From a point of view, there are no Koide doublets. If we define Koide's relationship as coming from three matrix conditions:

with
1) A multiple of the identity
2) B traceless
3)

Then the 3 in the 3/2 factor is really the dimension of the matrix, and thus the factor is 2/2 for Koide's doublets and 1/2 for Koide "singlets". So in this sense there are no Koide doublets.

...

I though it was after 2007, because when in December 2006 the topic was raised by Alain Connes, I just answered the usual folklore: "You need at least three for CP violation".

But in July 2005 I raise the topic of composite supersymmetry in this blog post
http://conjeturas.blogia.com/2005/07...-del-muon-.php
(regretly my other blog, "El ultimo hovercraft", was lost after a wrong backup)
The my webpage has a pdf dated...

pg 1147 ff of Castellani et al are informative.