Recent content by Gavran

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    I What's the physical meaning of Curl of Curl of a Vector Field?

    There are two Laplace operators, the scalar Laplacian and the vector Laplacian. The Laplacian ## \nabla^2 ## used in the equation $$ \nabla \times (\nabla \times \mathbf A) = \nabla (\nabla \cdot \mathbf A) - \nabla^2 \mathbf A $$ is the vector Laplace operator...
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    I EM field and EM wave

    Whenever a charged particle is accelerated or decelerated electromagnetic radiation will be produced. The only condition for generating an electromagnetic field in the near-field region and in the far-field region is a charged particle with changing its velocity.
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    Engineering Determine the resultant of the coplanar forces

    The method is correct. The result ## R=\sqrt{100^2+200^2}=\sqrt{50000} ## should be rounded to what the answer is.
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    How electricity distributers achieve equal phase loads?

    The duty of current balancing is solidarity of both of electricity suppliers and customers. The utilities must do it for voltage balancing by equally distribution of single-phase customers between three phases, while they can do nothing for voltage balancing by equally distribution of...
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    What is the difference between the two sine rules for resultant vector?

    There are four rules and they are the law of sines, the law of cosines, the law of tangents and the law of cotangents. The law of sines and the law of cosines are more common than the law of tangents and the law of cotangents. The law of sines and the law of cosines can be used for finding a...
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    Condition for coplanarity of two lines

    Mistakes are learning experiences.
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    Condition for coplanarity of two lines

    The condition for coplanarity of two lines ## \frac{x-x_1}{a_1} = \frac{y-y_1}{b_1} = \frac{z-z_1}{c_1} ## and ## \frac{x-x_2}{a_2} = \frac{y-y_2}{b_2} = \frac{z-z_2}{c_2} ## can be written as a triple product and in the next form ## ((x_2-x_1)\hat i + (y_2-y_1)\hat j + (z_2-z_1)\hat k) \cdot...
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    Is the power delivered by 1 no. of 3 phase system the same as 3 no. of 1-phase system?

    There is an article (https://en.wikipedia.org/wiki/Polyphase_system) and there is an introduction in the article and there is a sentence in the introduction which claims that compared to a single-phase, two-wire system, a three-phase three-wire system transmits three times as much power for the...
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    I Calculating the inverse of a function involving the error function

    The inverse function $$ F^{-1}(x) $$ of the cumulative density function $$ F(x) = erf(\frac{x}{2a}) – \frac{x}{\sqrt\pi a} exp(-\frac{x^2}{4a^2}) $$ can not be expressed in an analytic form.
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    Electronic Circuits - Calculate voltage

    It is impossible to solve this problem using only two rules, the junction rule expressed by $$ I_1 + I_2 = I_3 $$ and the rule expressed by $$ v_1 = I_3 R $$ which is called Ohm’s law. Here must be applied one more rule, the loop rule (https://en.wikipedia.org/wiki/Kirchhoff%27s_circuit_laws)...
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    Is the power delivered by 1 no. of 3 phase system the same as 3 no. of 1-phase system?

    In Europe when delivering 3 phase power to the panelboard there is the same line-to-neutral voltage on all three phases and that means all three phases together can deliver three times as much power as one of them. In North America when delivering 3 phase power using a high-leg delta there is...
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    Is the power delivered by 1 no. of 3 phase system the same as 3 no. of 1-phase system?

    A three-phase system can serve as three single-phase systems and it can be said a three-phase system can deliver three times as much power as a single-phase system. For high-leg delta three-phase systems this can not be said.
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    I Why Do Some Theorists Claim Cosmic Inflation Dilutes Magnetic Monopoles?

    The equation $$ \vec \nabla \cdot \vec B = 0 $$ rules out the existence of magnetic monopoles but there is another equation $$ \vec \nabla \cdot \vec B = \mu _ 0 \rho _ m $$ which includes the existence of magnetic monopoles.
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    B Deceptively simple geometry question on SAT test

    After including time instead of angle in the equations $$ x \left ( \theta \right ) = \left ( R + r \right ) \cos \theta – r \cos \left ( \frac { 3 r + r } { r } \theta \right ) $$ $$ y \left ( \theta \right ) = \left ( R + r \right ) \sin \theta – r \sin \left ( \frac { 3 r + r } { r } \theta...
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