Oh of course, I am sorry.
I would say that the mass point positions is in the height of 10m...
To get the speed I assume that I have to do the derivitation and then I have to calculate the speed for the value of t=1. is it right?
The function x (t) = 4 (m · s) t − 1 + 10 m describes the position of a mass point. In which direction does the speed point at time t = 1 s? Is the amount of speed constant or not? does the velocity function change its sign for t> 0 at some point? And in which direction does the acceleration...