No,I'm not trolling.
Like I said many times, I know HX is not a haloacid. But you didn't say HX. You said HX acids. That's where I got confused.
You said HX acids, not just HX. Since HX = halogen then I thought HX acids was referring to haloacids.
Anyway, I think I get it now...
I know exactly what you are saying that HX is NOT a haloacid. What I am talking about is what you said earlier. You said
Strength of HX acids is HI > HBr > HCl > HF - that's where the acidity grows down the period. But it doesn't mean haloacids will behave the same way, as their acidity...
I know HF is not a haloacid and that it is a hydrogen halide.
but it says ""Strength of HX acids is HI > HBr > HCl > HF " "
Strength of HX acids = haloacids? no??
If so, Can you give me an example where ""Strength of HX acids is HI > HBr > HCl > HF " "
Yes I am quite confused at this moment.
So for Br-CH2-COOH and F-CH2-COOH, which one is more acidic? We said that F-CH2-COOH is more acidic because F is more electronegative, but at the same time, "Strength of HX acids is HI > HBr > HCl > HF "
?
BR-CH2-COOH vs. F-CH2-COOH
Would the one with fluorine be more acidic because it is more electronegative? But I thought when they are in the same column, acidity in the haloacids increases as we move down the column. Does that mean only if we are comparing haloacids on their own without...
But if I go to this website, and do the question at the very bottom...
http://chemwiki.ucdavis.edu/Organic_Chemistry/Organic_Chemistry_With_a_Biological_Emphasis/Chapter__7%3A_Organic_compounds_as_acids_and_bases/Section_7.3%3A_Structural_effects_on_acidity_and_basicity
The solution says that...
Homework Statement
Rank by acidity
Homework Equations
Br is lower on the periodic table, hence more acidic. But in the first compound, it is also farthest away from the carboxylic acid, which one gets priority ? The Attempt at a Solution
I think The one with the bromo group closest to the...
Yes! That's what I've been doing all along!
mg(22) = mg (2) + KE
HOWEVER, I was using the mass of BOTH blocks for the RIGHT side.
I think I get it now. Thanks!
Thank you for your reply.
At the very beginning, it says the 2kg block is at rest so v=0 so no KE, only PE. Isn't it?
I don't really get why the kinetic energy of the sliding block is mgΔh. The PE of the block at the very beginning is 2*9.8*22
When it has joined with the other block...
But the mass are different. At the beginning, there's only PE, but at the bottom there is both PE and KE as some of the PE has been converted to KE?
mgh = mgh + 0.5*m*v^2
2*9.8*22 = 7*9.8*2 + 0.5*7*v^2
Where did I go wrong?