Recent content by Mister T

Some coins have ridges that act like little gear teeth. But I meant friction between the coins and the surface they rest on.

You have to apply a force to make the coin move. Anytime you stop applying the force the coin stops moving (due to friction). When you move the coin you have to rotate it yourself in such a way that it doesn't slip against the coin in the center.

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If the potential is uniform (same everywhere) then the field is zero.

It could have been specified elsewhere that the potential is taken to be zero at infinity. That is likely the convention used by the author.

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We can play that game forever. How do you define define? How do you define how? How do you define interaction. We've already done that! How do you define specific? Seems you are now being less specific? And silly!

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How far away, and in what direction, from the origin.

My guess 2 was meant to eliminate several possibilities, but it turned out to be a decent guess that left me with only one choice.

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Angular momentum of a system is conserved when the net torque on the system is zero. You should be able to find a statement like this in the textbook section on conservation of angular momentum.

That would be true only if the collision were perfectly elastic. In other words, the bullet loses some energy and the rod gains some energy, but the two amounts of energy are equal only if the collision is perfectly elastic (which it isn't). The net torque. That just means the torque due to...

So, can you calculate how much energy was lost? Is the rod moving after the collision? If some is lost then it's not conserved. Can you calculate how much? Remember, momentum is a vector quantity. What is the condition that must be satisfied if angular momentum is conserved? No! All the...