Inside a dark room, when light comes through a hole, we see the dust particles as the particles scatter the light. But, when the whole window is open, we don't see the dust particles scattering the light. Why?
The room does not appear blue because the amount of blue light scattered by the atmospheric particles in the room is too low to be experienced by a naked eye.
The room not appearing blue does not rule out the scattering of light due to atmospheric particles inside the room.
I am trying to understand our experience of presence of light in the space between two walls of a room.
Here, I learnt that the light reflected from different objects e.g. tree or building reaches the room
and makes things visible in the room. The reflected light either from the outside objects...
Yes, but looking at this space we can say whether there is light or not.
Vacuum is transparent. And if instead of atmospheric particles, we have vacuum inside the room, then the space will appear dark. The space doesn't appear dark. This implies that the atmospheric particles do scatter visible...
Do you mean that the walls of the room reflect the light and we experience that light?
In this case, we see the colour of the wall. I am talking of the space between the walls. This space doesn't appear dark to us. So, some light does enter the eye. Although, I don't see any colour of the...
Using the sun as a light source, why do we experience the presence of light in a room with open windows even when direct sunlight is not coming to the room?
A possible explanation:
We don't see the light in the room, yet we experience it.
A part of the atmosphere is present in the room. The...
Taking the shape of water drop to be spherical with radius R and ignoring the gravity, three forces acting on the surface of the water drop are
1) force ##F_o## in radially inwards direrction due to the outside pressure ##P_o##
2) force ## F_{in}## in radially outward direction due to the...
Let's consider an uncovered glass. Air particles are present in the glass.
$$ P_1 = P_a$$ $$P_2 =P_1 +\rho gh = P_a +\rho g h$$where ##P_A## is atmospheric pressuere and ##\rho ## is air density.
Now, if I cover the glass with a plastic card, then what is ## P_1##?
$$P_2 =P_1 +\rho gh $$
1)...
Since there is only one excited electron, it could come from n=3 to n =1directly or n=3 to n =2 and then n=2 to =1.
Hence, there could be one or two lines depending upon the path taken by electron.
Is this right?