Recent content by takelight2

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    Electric field inside a charged ring

    I am just a bit confused here. Would doing this even change the electric field direction at the center at all? I'm thinking no, but a bit of direction would be appreciated. This problem is really simple, I'm just a bit confused.
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    Help with this thermodynamics and entropy question please

    So I've answered the first question and I got a final temp of 42.06 Celsius. Now for this second one, I don't know why I am getting it wrong: Im doing 0.215*ln(315.06/291.46) + 1*ln(315.06/319.91) But it says I am wrong. What about my process is faulty?
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    Solve Rocket Problem with Step-by-Step Guide | Imaginary Number Solution

    Oh yeah that makes sense. So that would change my final equation to this: u = sqrt[([(s/t)+(1/2)(g)(t)]^2) -2gh] But it still is giving me the wrong value D: Any other ideas?
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    Solve Rocket Problem with Step-by-Step Guide | Imaginary Number Solution

    This is what I tried and it makes perfect sense to me. When i plug in the numbers to what I ended up with, I get an imaginary number for U initial... Work is attached below.
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    Help with centripetal force and friction question please

    Tangential acceleration or centripetal acceleration, its a = v^2/r. So would be, 37.04^2/200 = 6.86 m/s^2. How does that help though?
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    Help with centripetal force and friction question please

    Ff = Fc (mv^2)/r = kmg (v^2)/r = kg v^2 = kgr v^2 = 0.7*9.8*200 v = 37.04 m/s I chose option e, and its wrong. What am i doing wrong here?
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    Help with this Ferris wheel rotational physics problem please

    Oh ok. So then i can just change a2= -ac +9.8, making downward positive. Ok thanks a lot.
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    Help with this Ferris wheel rotational physics problem please

    So this is what I've attempted: 666 = m*a1 510 = m*a2 a1= ac + 9.8 a2= ac-9.8 666 = m(ac+9.8) 510 = m(ac-9.8) 666 = m*ac + m*9.8 510 = m*ac - m*9.8 156 = 2m(9.8) m = 7.9 kg (which seems very wrong haha) any ideas?? I thought my reasoning was okay, since I considered that at the top of...
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    Help with these rocket launch questions please

    It would be -9.8 right? since its opposite the direction of motion..?
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    Help with these rocket launch questions please

    Thanks for the help. I tried the things you said, and ended with the following system of equations: ## 9 = ut + \frac{1}{2}(-9.8)t^2 ## ## 11.2 = u(t+0.17) + \frac{1}{2}(-9.8)(t+0.17)^2 ## Now, I don't really find a way to solve this system, and it seems to be overly complicated? Am I doing...
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    Help with these rocket launch questions please

    I know that a=-9.8, I am having trouble aplying the motion equations. For example, I can't use equations that have velocity (either initial or final), so I can rule out those equations. I am then left with no equations to use. I am extremely stumped.
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