zenterix's latest activity

I think the simplest thing to consider is just like, consider the curve sketched out by##(t,t^2)## compared to ##(t^3,t^6)##. Both of...

What is the fundamental law that you are using to set up this equation? You might be missing a factor of ##\epsilon_0##.

If you are going to quote the Ampere-Maxwell law, quote it correctly. The displacement current term (Maxwell's correction) is ##\mathbf...

OK, but here you forgot a time derivative.

Indeed $$\oint \vec{B}\cdot d\vec{s}=\mu_0\left (\iint_S \vec{J}\cdot\hat{n}dA+\epsilon_0\frac{d}{dt}\iint_S \vec{E}\hat{n}dA\right )$$...

Indeed you are correct. I forgot a factor of ##\epsilon_0##. $$\oint \vec{B}\cdot d\vec{s}=\mu_0\left (\iint_S...

Here is a picture depicting the capacitor and the points of interest. I approached this problem by applying the Ampere-Maxwell law...

The notes go on as follows This is all fine. The velocity field is represented by the initial system of equations. What is the...

If ##x## and ##y## are functions of ##t## and we eliminate the ##t## to get an equation with only ##x## and ##y## in it and then move...

Here are the notes. We have the system $$\begin{bmatrix} x'\\y' \end{bmatrix}=\begin{bmatrix}f(x,y)\\g(x,y)\end{bmatrix}\tag{1}$$ We...

Here are a few things to note - By finding an eigenvalue ##\lambda_1## and an associated eigenvector ##\vec{v}_1##, you have found a...

For the record, perhaps one might ask why I am not embracing phasor diagrams currently. I guess it is because I don't have a solid...

Finding the amplitude of ##I## is actually simple. $$I(t)=V_0\left ( \frac{1}{R}\sin{(\omega t)}+\cos{(\omega t)}\left (\omega...

If we apply KVL to the three separate loops involving the AC voltage we obtain expressions for ##I_R, I_L##, and ##I_C##...

One other thing I tried to do to find the capacitor voltage (while taking into account the hint) was to try to force ##q(0)=0##. After...