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Old Nov1-09, 04:14 AM                  #1
Petar Mali

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Exited states configuration

Litium has a structure

LaTeX Code: 1s^22s^1

What is the first exited state of litium?


I have some doubt? I think that it is

LaTeX Code: 1s^22p^1

Is it correct or maybe

LaTeX Code: 1s^23p^1

Why I'm in problem. Because wave function of hydrogen atom depends of three quantum numbers
LaTeX Code: \\psi_{n,l,m} but energy depends only of one quantum number LaTeX Code: E_n . So we have degeneration. In this logic it's need to be LaTeX Code: 1s^23p^1 . But I don't have hydrogen I have litium, so must be some ecranisation and of course Hund rule LaTeX Code: s and LaTeX Code: p orbitals have different energy. And I can say that

LaTeX Code: E_{n,l}=-13,6eV\\frac{1}{(n-\\Delta l)^2}

Thanks for your answer!
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Old Nov1-09, 05:28 PM                  #2
Bob S

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Re: Exited states configuration

See
http://physics.nist.gov/cgi-bin/Ioni...php?element=Li
Bob S
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Old Nov3-09, 05:58 PM                  #3
Petar Mali

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Re: Exited states configuration

Thanks!
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