- #1
yungman
- 5,755
- 293
I have a discussion about shielding of noise generated by appliance and florescent lights. I know both Al and Cu are not magnetic material. BUT all noise are time varying meaning it is EM field. Good conductor block E field as loss is very high. How does that work when only the B field can pass through?
Does the B that pass through create back the E field by Maxwell's equation
[tex]\nabla \times \vec E =-\frac{\partial \vec B}{\partial t}[/tex]
So the E field is regenerate again after passing through the good conductor sheet?
Another question, does the thickness of the copper or aluminum sheet matter on the shielding. If so, why?
Thanks
Alan
Does the B that pass through create back the E field by Maxwell's equation
[tex]\nabla \times \vec E =-\frac{\partial \vec B}{\partial t}[/tex]
So the E field is regenerate again after passing through the good conductor sheet?
Another question, does the thickness of the copper or aluminum sheet matter on the shielding. If so, why?
Thanks
Alan