- #1
something_about
- 27
- 0
hello
First question-Internal energy W(I) of an ideal gas consists only of internal kinetic energy (thermal energy) W(KE).
W(I) = W(KE)
If at temperature T there are N molecules in an ideal gas,then total W(I) is
W(I) = N*3/2*k*T
We see from above formula that W(I) of ideal gas depends on number of molecules (N) and temperature T, but it doesn't depend on type of gas, that is it doesn't depend on what mass of gas molecules is.
M - relative molecule mass
u - 1.66*10^(-27)
But since N = m / (M*u)
W(I)=m*(3*k/2*M*u)*T
W(I)=m*c*T
c - specific heat - (3k/2*M*u)
Specific heat depends on size of relative molecule mass of gas. Thus the heavier the molecules, the smaller is specific heat.
Individually formulas for both specific heat and for W(I) make sense, but when we include c into formula for W(I), it gets a little confusing. Looking at original formula we see that W(I) doesn't depend on relative molecule mass, but if we look at W(I) = m*(3k/2*M*u)*T, we see that W(I) does depend on M.
second question - In ideal gas W(I) = W(KE)
N...number of molecules
T...temperature
W(i)=N*3/2*k*T
I've read that From this formula we can conclude that W(I) doesn't depend on pressure and volume. If at T=const. the ideal gas is shrinked,its internal energy won't change.
How would this formula give us such a clue?
Doesn't pressure increase when gas is compressed? Doesn't that happen because the resultant force appears in the matter that resists further deformation?
Doesn't that casuse change in internal energy? Don't we supply external energy to gas if we try to compress it?
Or doesn't at least internal energy(part of it) transform from kinetic to some other form?
thank you
First question-Internal energy W(I) of an ideal gas consists only of internal kinetic energy (thermal energy) W(KE).
W(I) = W(KE)
If at temperature T there are N molecules in an ideal gas,then total W(I) is
W(I) = N*3/2*k*T
We see from above formula that W(I) of ideal gas depends on number of molecules (N) and temperature T, but it doesn't depend on type of gas, that is it doesn't depend on what mass of gas molecules is.
M - relative molecule mass
u - 1.66*10^(-27)
But since N = m / (M*u)
W(I)=m*(3*k/2*M*u)*T
W(I)=m*c*T
c - specific heat - (3k/2*M*u)
Specific heat depends on size of relative molecule mass of gas. Thus the heavier the molecules, the smaller is specific heat.
Individually formulas for both specific heat and for W(I) make sense, but when we include c into formula for W(I), it gets a little confusing. Looking at original formula we see that W(I) doesn't depend on relative molecule mass, but if we look at W(I) = m*(3k/2*M*u)*T, we see that W(I) does depend on M.
second question - In ideal gas W(I) = W(KE)
N...number of molecules
T...temperature
W(i)=N*3/2*k*T
I've read that From this formula we can conclude that W(I) doesn't depend on pressure and volume. If at T=const. the ideal gas is shrinked,its internal energy won't change.
How would this formula give us such a clue?
Doesn't pressure increase when gas is compressed? Doesn't that happen because the resultant force appears in the matter that resists further deformation?
Doesn't that casuse change in internal energy? Don't we supply external energy to gas if we try to compress it?
Or doesn't at least internal energy(part of it) transform from kinetic to some other form?
thank you