- #1
chrispat
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Homework Statement
A person of mass 60kg standing on a horizontal floor attempts to push a large wheeled crate of mass 800kg, which can roll on the same horizontal floor with coefficient of rolling friction equal to ur=0.03. What is the minimum coefficient of friction required between the soles of the person's shoes and the horizontal floor if the person is to succeed in keeping the crate rolling at a constant speed without slipping herself?
I don't understand what force is moving the person forward but I have attempted a solution
Homework Equations
For the crate:
Ff<---crate--------->Fpush
Fnet=Fpush-Ff=0
For the shoe shoes:
Ff<---ss---------->Fpush
Fnet=Fpush-Ff=0
The Attempt at a Solution
For the crate:
Ff=(ur)(m)(g)
=(0.03)(800kg)(9.81m/s^2)=235N
For the shoe soles:
Fnet=(235N)-(us)(60kg)(9.81m/s^2)
us=235/(60)(9.81)=0.399