Originally posted by Ambitwistor
If you, for instance, measure the ratio of the circumference of a circle to its diameter, and it doesn't come out to π, space is not flat, by definition.
Which type of circle do you mean? A circle of space? What would that mean?
No, you can only measure an object. There is a gedanken experiment, the Ehrenfest disk. If it is rotated with high speed it should break because the periphery contracts. This has to do with the fact that fields contract in motion. And this again was known in classical physics before Einstein started to develop relativity.
Lots of people weren't happy with the theory when it first came out. That's because it was new and different, and didn't have much experimental support.
Roman Sexl was to my knowledge one of the best known specialists for relativity worldwide. He died middle of the 1980ies. No one should guess that he did not understand relativity.
An amusing claim, considering that (a) you don't have a theory of gravity, and (b) you don't know if the theory you do have works.
I do not have and I do not need a specific theory of gravity. I refer mostly to classical physics. Refraction is not my invention but really classical physics, and it does happen in the context we discuss here. Refraction is not at all an option but an inevitable fact. The only special point is that I use particle physics as well. I use the internal oscillation of a particle as it follows from the Dirac equation for the electron, and I assume the same oscillation for a quark. Nothing more is necessary!
As I said, I do not accept repeated assertions, only derivations and proofs. You can claim all you want that thus-and-such follows from your theory, but you have not demonstrated it.
Of course I have. Please look to page 2 of my gravity website. I deduce from refraction:
a = 2*GM/r^2 (for a light like object; for an object at rest it is half of it).
This equation does not contain any parameters of the test-mass under acceleration. So it is a direct proof of equivalence.
What do you mean by "explains this"? You can derive the equivalence principle from the axioms of either Newton's or Einstein's theory.
The equivalence principle was not derived from axioms of either Newton's or Einstein's theory, but it is an axiom in both theories. In the refraction calculation on the other hand it is a deduced consequence.
Light cannot escape GR black holes at all.
Can you please refer to an experiment which proves this?
General relativity's prediction is r = 3GM/c2 for a circular photon orbit. It is r = 2GM/c2 for the Schwarzschild radius.
Thank you for this information. This is a good point to decide which way is correct. Can you please also for this case tell us an experiment (or direct observation) which can be used to make a decision?
Originally posted by russ_watters
Time, space, mass, heat, etc are words invented by humans which are used to describe very real and measurable things.
True, the words are all human inventions. But the word "size" (of an object) means something different than "space". And the size of something is measurable, space is not measurable.
An example from special relativity: It was known, before relativity came up, that fields are contracted during motion (Fitzgerald, Lorentz, Lodge, Heaviside etc). This comes fundamentally from the limited velocity of light by which field changes propagate. If it is now stated that not the field shrinks but space itself shrinks, this is of a different quality. And I doubt (as e.g. Lorentz did until the end of his life in the 1930ies) that this is a practical approach.
You cannot change definitions
I do not change definitions. But I try to show that the classical understanding of space and time was a practical one (not my invention), and that it is more related to a physical (instead of geometrized) understanding of the world to assume e.g. the contraction of objects rather than the contraction of space. Because we have very concrete physical causes for the contraction of objects; we do not have any similar for space.