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myvow
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For this question,why Ka =(ch3coo-)(h+)/(ch3cooh) instead of Ka =(ch3coo +x)(x)/(ch3cooh-x) ?
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myvow said:why Ka =(ch3coo-)(h+)/(ch3cooh) instead of Ka =(ch3coo +x)(x)/(ch3cooh-x)
myvow said:For this question,why Ka =(ch3coo-)(h+)/(ch3cooh) instead of Ka =(ch3coo +x)(x)/(ch3cooh-x) ?
A buffer solution is a solution that resists changes in pH when small amounts of acid or base are added. It is composed of a weak acid and its conjugate base (or vice versa) and is able to maintain a relatively constant pH by absorbing or releasing H+ ions.
A buffer solution maintains equilibrium by having a relatively large amount of both the weak acid and its conjugate base present. When an acid or base is added, the buffer components react with it to form a weaker acid or base, respectively. This shift in equilibrium helps to keep the overall pH of the solution stable.
Yes, buffer solutions can be made using organic compounds. Many organic acids, such as acetic acid, and their conjugate bases can be used to create buffer solutions. These types of buffers are commonly used in biological and biochemical experiments.
The buffering capacity of a solution can be affected by the type and concentration of organic compounds present. Generally, the higher the concentration of the buffer components, the greater the buffering capacity. Additionally, the pKa (acid dissociation constant) of the organic compound used can also impact the buffering capacity of the solution.
Yes, buffer solutions can be used in non-aqueous systems. Non-aqueous buffer solutions are commonly used in organic chemistry experiments or in industrial processes. They are composed of a weak acid and its conjugate base in a non-aqueous solvent, such as an organic solvent or liquid paraffin.