commelion said:
Yes, I think so.
Hmm, there are some things not clear in your rule of thumb there. I surmize that the method you are following is to design a low-pass LR filter having a bandwidth = 20% of the output frequency. That's fair enough.commelion said:
NascentOxygen said:Hmm, there are some things not clear in your rule of thumb there. I surmize that the method you are following is to design a low-pass LR filter having a bandwidth = 20% of the output frequency. That's fair enough.
Your formula 1/((2pi (L /R)) looks appropriate, too. But from where did you pluck your value for R? You seem to be assuming R equals 10Ω, though I can see nothing in the question that could lead to this or any other value.
The purpose of calculating the inductor is to determine the appropriate size and value of the inductor needed in a 3-phase rectifier circuit in order to achieve a ripple of less than 20% in the output voltage.
The main factors that affect the calculation of the inductor are the input voltage, output voltage, and load current. The frequency of the input voltage and the desired ripple percentage also play a role in the calculation.
The inductor can be calculated using the formula L = (Vout * T) / (ΔIL * Vin), where L is the inductor value in Henrys, Vout is the output voltage, T is the period of the input voltage, ΔIL is the desired change in inductor current, and Vin is the input voltage.
The units for inductor values in this calculation are Henrys (H). However, in practical applications, inductors are often measured in milliHenrys (mH) or microHenrys (μH).
Achieving a ripple of less than 20% ensures a more stable and consistent output voltage, which is important for the proper functioning of electronic devices that rely on a steady power supply. A lower ripple also reduces the chances of damaging sensitive components in the circuit due to fluctuations in voltage.