- #1
mooncrater
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Homework Statement
The question is :
"A step down transformer having turns ratio 10:1 and input 230 V,50 Hz is used in a half wave rectifier. The diode forward resistance is 15 ohms and resistance of secondary winding is 10 ohms . For a load resistance of 4 kilo ohms, calculate the average and R.M.S values of load current and voltage".
Homework Equations
$$I_{R.M.S}=I_{MAX}/2$$
$$I_{avg}=I_{MAX}/pi$$---(For a half-wave rectifier)
$$I_{R.M.S}=V_{R.M.S}/R_{Total}$$
$$E_{s,R.M.S}/E_{p,R.M.S}=N_2/N_1$$
The Attempt at a Solution
So, using the ##4^{th}## equation :
##E_{s,R.M.S}/230=1/10##
So,
$$E_{s,R.M.S}=23 V$$
Because of which,
$$ I_{R.M.S}=23/(4025) A$$
So , ##I_{R.M.S}=5.71 mA##
But even looking at the answer at this point of time , I realized that both of these answers were wrong.
The given value of ##E_{R.M.S}=16.1624 V## and ##I_{R.M.S}=4.0406 mA ##
so, where am I wrong ?