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liberalgeek
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a force F of 2n is applied to a plunger with a crossectional area of 2.5*10^-5m, the area of the needle is 1*10^-8 sq meters, the static pressure every where is 1 atmopshere, it is horizontal, and it is filled with water. what is the velocity of the water exiting. please help.
i know that the equation should reduce to this:
f=p*a
2n=p*a
2n=p*2.5*10^-5
pp1=80000
101325+80000=181325pa=P1
pp2=2/1*10^-8=200000000
pp2+101325=p2=200101325
P1+1/2*d*v1^2+dgh1=P2+1/2*d*v2^2+dgh2
H1=h2
P1+1/2*d*v1^2=P2+1/2*d*v2^2
is this right, and if so, how do i get v, if not what is wrong
i know that the equation should reduce to this:
f=p*a
2n=p*a
2n=p*2.5*10^-5
pp1=80000
101325+80000=181325pa=P1
pp2=2/1*10^-8=200000000
pp2+101325=p2=200101325
P1+1/2*d*v1^2+dgh1=P2+1/2*d*v2^2+dgh2
H1=h2
P1+1/2*d*v1^2=P2+1/2*d*v2^2
is this right, and if so, how do i get v, if not what is wrong
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