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Homework Statement
What is the electronic transition of He II when it emits 468.6 nm photon.
Homework Equations
[tex]\frac{1}{\lambda}=4R\left(\frac{1}{m^2}-\frac{1}{n^2}\right)[/tex]
The Attempt at a Solution
I know it is a pashen-alpha line from googling but I don't know how to find that from this equation with two unknowns. I know the energy levels are discrete so there is probably only one transition that makes this wavelength. Don't know why He II and not He I so I might be missing something.