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ProAgnusDei
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Homework Statement
Two parallel plates labelled W (negative) and X (positive) are separated by 5.2 cm. The electric potential between the plates is 150 V. An electron starts from rest at time tw and reaches plate X at time tx. The electron continues through an opening in plate X and reaches point P at time tP. Determine the speed at tx and tP
e = -1.6 x 10-19 C
me = 9.1 x 10-31
Homework Equations
V = kq1 / r
ΔV = ΔE/q
ε = ΔV / r
Ek = 0.5mv2
The Attempt at a Solution
I'm not sure how to determine v at tw and tx, but I did find the field strength: ε = 2884.6. We also know the electron starts from rest, so we could use the conservation of energy law to generate the following eq'n.
v2 = 2m-1kq1q2(ra-2 - rb2). But we don't have a "q2" so I'm quite lost. Any help is appreciated!
God bless and thanks!