Electric Flux Density: 4.5Xe + .50MV/m

In summary, the value of 4.5Xe + .50MV/m represents the electric flux density vector in a given region of space, with "e" representing the unit vector and "MV/m" representing the strength of the electric field. Electric flux density and electric field strength are related but different concepts, with electric flux density measuring the electric field per unit area and electric field strength measuring the force per unit charge. Electric flux density can be negative, indicating an opposite direction of the electric field. The magnitude of electric flux density is affected by the electric field strength, size and shape of the charged object, distance from the object, and the permittivity of the medium. It can be calculated by dividing the electric flux by the
  • #1
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Homework Statement


Given Xe=4.5 and E=.50 MV/m find the displacement flux density

Homework Equations


D=ε0εrE
εr=1+Xe

The Attempt at a Solution


Using the equation above I get (8.85e-12)(5.5)(.50e6)=.000024338 C/m^2 which is not what the answers say they give it in nC which I can't see how they can do?
 
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  • #2
Sorry they give it in nC/m^2
 
  • #3
Actually looking at it the real units are μC/m^2
 
  • #4
Should it be 24.338μC/m^2
 
  • #5


It is possible that the given values for Xe and E are incorrect or not in the correct units. Without knowing the context or specific problem, it is difficult to determine the correct solution. It is also important to note that electric flux density (D) is usually measured in units of Coulombs per square meter (C/m^2), not nanoCoulombs (nC). It is best to double check your calculations and units to ensure accuracy.
 

Related to Electric Flux Density: 4.5Xe + .50MV/m

1. What does the value of 4.5Xe + .50MV/m represent in terms of electric flux density?

The value of 4.5Xe + .50MV/m represents the magnitude and direction of the electric flux density vector in a given region of space. The "e" represents the unit vector in the direction of the electric field, while "MV/m" represents the strength of the electric field in terms of megavolts per meter.

2. How is electric flux density different from electric field strength?

Electric flux density and electric field strength are related but distinct concepts. Electric flux density is a measure of the electric field per unit area, while electric field strength is a measure of the force per unit charge experienced by a test charge in an electric field.

3. Can electric flux density be negative?

Yes, electric flux density can be negative. A negative value indicates that the electric field is directed in the opposite direction of the unit vector "e". This can occur near negative charges or in regions of space where the electric field is changing in direction.

4. What factors affect the magnitude of electric flux density?

The magnitude of electric flux density is affected by the electric field strength, the size and shape of the charged object, and the distance from the charged object. It is also dependent on the medium in which the electric field exists, as different materials can have different permittivity values.

5. How is electric flux density calculated?

Electric flux density is calculated by dividing the electric flux, which is the total number of electric field lines passing through a given area, by the area itself. It can also be calculated by multiplying the permittivity of the medium by the electric field strength.

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