Find the Electric field due to an electric dipole at the origin

  • #1
MatinSAR
562
179
Homework Statement
Find electric field due to dipole at any point using ##\vec E=-\nabla \phi##.
Relevant Equations
##\vec E=-\nabla \phi##
Question :

1699296919913.png


I have tried to solve but I struggle with this part:
1699297291071.png

Any help would be appreciated.
 

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  • #2
Just expand the dot product and ##\vec r## then take derivatives.$$(\vec p\cdot \vec{\nabla})\vec r = \left(p_x\frac{\partial}{\partial x}+p_y\frac{\partial}{\partial y}+p_z\frac{\partial}{\partial z}\right)(x~\hat x+y~\hat y+z~\hat z)$$
 
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  • #3
kuruman said:
Just expand the dot product and ##\vec r## then take derivatives.$$(\vec p\cdot \vec{\nabla})\vec r = \left(p_x\frac{\partial}{\partial x}+p_y\frac{\partial}{\partial y}+p_z\frac{\partial}{\partial z}\right)(x~\hat x+y~\hat y+z~\hat z)$$
Then it is equal to ##Pr^{-3}##, Am I right?!
 
  • #4
Show me the math.
 
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  • #5
kuruman said:
Show me the math.
1699298882251.png

Sorry that ##r^{-3}## was related to another part.
 
  • #6
I have used:
##p_x\frac{\partial}{\partial x}y=0##
##p_x\frac{\partial}{\partial x}z=0##
##p_y\frac{\partial}{\partial y}x=0##
##p_y\frac{\partial}{\partial y}z=0##
##p_z\frac{\partial}{\partial z}x=0##
##p_z\frac{\partial}{\partial z}y=0##

##p_x\frac{\partial}{\partial x}x=p_x##
##p_y\frac{\partial}{\partial y}y=p_y##
##p_z\frac{\partial}{\partial z}z=p_z##
 
  • #7
MatinSAR said:
I have used:
##p_x\frac{\partial}{\partial x}y=0##
##p_x\frac{\partial}{\partial x}z=0##
##p_y\frac{\partial}{\partial y}x=0##
##p_y\frac{\partial}{\partial y}z=0##
##p_z\frac{\partial}{\partial z}x=0##
##p_z\frac{\partial}{\partial z}y=0##

##p_x\frac{\partial}{\partial x}x=p_x##
##p_y\frac{\partial}{\partial y}y=p_y##
##p_z\frac{\partial}{\partial z}z=p_z##
Yes. What is your final answer when you put it all together?
 
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  • #8
kuruman said:
Yes. What is your final answer when you put it all together?
##\vec P## , I guess.
 
  • #9
Sorry, not that. I meant putting together the final expression ##\vec E=-\vec{\nabla}\psi=?##
 
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  • #10
kuruman said:
Sorry, not that. I meant putting together the final expression ##\vec E=-\vec{\nabla}\psi=?##
I am trying to solve ... I will send the work.

Thanks again for your help Prof.Kuruman🙏.
 
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  • #11
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  • #12
That's it. Good job!
 
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  • #13
kuruman said:
That's it. Good job!
Thanks a lot! Have a good day.
 
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