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Homework Statement
Suppose f(x) = x2 + x + 1, a = 1, and L = 3. Find a value d > 0 such that 0 < |x - a| < d implies |f(x) - L| < 1/100
Homework Equations
The Attempt at a Solution
Given 0<|x-1|<d implies 0<|x2 + x + 1 - 3|<1/100
0< x2 + x + -2 <1/100
0<(x+2)(x-1)<1/100
Assume
0<|x-1|<1
1<x<2
3<x+2<4
Then
3|x-1| < (x+2)|x-1| < 4|x-1| < 1/100
We need
4|x-1| < 1/100
|x-1| < 1/251/25 < 1, therefore d should be 1/25.