Flux density in magnetic circuit

[DODGEVIPER13]

Homework Statement

Consider the magnetic circuit shown in figure 3
Assuming that the core (μr=1000) has a uniform cross section of 4 cm^2, determine the flux density in the air gap the picture is very small so here are the values L=42cm, Ig=0.1cm, turns=500, and I=0.2A

Homework Equations

Flux=magnetomotive force/reluctance or NI/((L/μ0(μr)A)+(G/Aμ0))

The Attempt at a Solution

When I plug the values given in the problem statements and figure 3. I get .000035493 I am not sure of the units however?

 

[DODGEVIPER13]

Is the problem not clear?

 

[DODGEVIPER13]

Common guys give me a push or something

 

[DODGEVIPER13]

Hey is this correct guys? Anything?

 

[rezeew]

I would like to clarify that the units for flux density are Tesla (T) or Gauss (G). In this case, the flux density in the air gap would be 0.00003549 T or 0.3549 G. Additionally, I would like to mention that the equation used to calculate flux density in a magnetic circuit is B = μ0μr(NI)/L, where B is the flux density, μ0 is the permeability of free space (4π x 10^-7), μr is the relative permeability of the core material, N is the number of turns, I is the current, and L is the length of the magnetic path. The air gap can be considered as a region with a very large reluctance, so it can be neglected in the equation. Therefore, the flux density in the air gap would be directly proportional to the current and inversely proportional to the length of the magnetic path. In this case, the flux density can be calculated as (4π x 10^-7)(1000)(500)(0.2)/0.42 = 0.00004762 T or 0.4762 G. I hope this helps clarify any confusion.