Hamiltonian which is invariant under time reversal question.

In summary, assuming that the Hamiltonian is invariant under time reversal, we have shown that the wave function for a spinless nondegenerate system can always be chosen to be real at any given instant of time.
  • #1
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Homework Statement


Assuming that the Hamiltonian is invariant under time reversal, prove that the wave function for a spinless nondegnerate system at any given instant of time can always be chosen to be real.



Homework Equations


[tex]\psi(x,t)=<x|e^{-iHt/\hbar}|\psi_0>[/tex]
The Time-Reversal operator: [tex]T^2=-1 \\ T|x>=|x> [/tex]
HT=TH.

The Attempt at a Solution


[tex]\psi(x,t)=<x|e^{-iHt/\hbar}|\psi_0>=<x|e^{-iHt/\hbar}TT^-1|\psi_0>=<x|Te^{iHt/\hbar}T^{-1}|\psi_0>=<x'|exp(-iHt/\hbar}|\psi
_0'>=<x|Texp(-iHt/\hbar)T^-1|\psi_0>=(1)[/tex]
[tex](1)=<x|exp(iHt/\hbar)|\psi_0>=\psi(x,t)*[/tex]
where the last line is assured because |x'>=T|x>=|x>, |\psi_0'>=T|psi_0>.
Is this fine as a proof or not?
 
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  • #2


Your proof is correct, but here is a more detailed explanation:

First, we know that the Hamiltonian is invariant under time reversal, which means that THT^-1=H. This means that the time-evolution operator, e^{-iHt/\hbar}, is also invariant under time reversal, i.e. Te^{-iHt/\hbar}T^-1=e^{-iHt/\hbar}. This is because the time-evolution operator is given by e^{-iHt/\hbar}=\sum_n c_n e^{-iE_nt/\hbar}|E_n>, where |E_n> are the eigenstates of the Hamiltonian and c_n are some coefficients. Since T commutes with H, it also commutes with e^{-iHt/\hbar}, and therefore T|E_n>=|E_n>. This means that T|psi_0>=|\psi_0>, where |psi_0> is the initial state of the system.

Next, we can rewrite the wave function at time t as \psi(x,t)=<x|e^{-iHt/\hbar}|\psi_0>. Using the fact that T|psi_0>=|\psi_0>, we can rewrite this as \psi(x,t)=<x|Te^{-iHt/\hbar}T^-1|psi_0>. Now, using the fact that Te^{-iHt/\hbar}T^-1=e^{-iHt/\hbar}, we get \psi(x,t)=<x|e^{-iHt/\hbar}|\psi_0>=<x|T^{-1}e^{-iHt/\hbar}T|psi_0>. Finally, using the fact that T^{-1}T=1, we get \psi(x,t)=<x|T^{-1}e^{-iHt/\hbar}T|psi_0>=<x|exp(iHt/\hbar)|psi_0>. This shows that the wave function at time t is equal to the complex conjugate of the wave function at time -t, i.e. \psi(x,t)=\psi^*(x,-t).

Since the wave function at any given instant of time t is equal to the complex conjugate of the wave function at time -t, we can always choose the wave function to be real by choosing t=0. This means
 

Related to Hamiltonian which is invariant under time reversal question.

1. What is a Hamiltonian that is invariant under time reversal?

A Hamiltonian that is invariant under time reversal means that the equations of motion derived from it remain the same when time is reversed. This implies that the system is reversible and time symmetric.

2. How is time reversal symmetry related to a Hamiltonian?

Time reversal symmetry is directly related to a Hamiltonian if the Hamiltonian is invariant under time reversal. This means that the Hamiltonian remains unchanged when time is reversed, and therefore the system is reversible and time symmetric.

3. Can a Hamiltonian be invariant under time reversal in all cases?

No, a Hamiltonian cannot be invariant under time reversal in all cases. It depends on the specific physical system and its properties. In some cases, the Hamiltonian may have terms that break time reversal symmetry, while in other cases, the Hamiltonian may be time reversal invariant.

4. What are the implications of a Hamiltonian being invariant under time reversal?

If a Hamiltonian is invariant under time reversal, it means that the system described by it is reversible and time symmetric. This has important implications in quantum mechanics, as it allows for the existence of degenerate energy levels and the possibility of time reversal of quantum states.

5. How is time reversal symmetry tested in a physical system?

Time reversal symmetry can be tested in a physical system by observing the behavior of the system when time is reversed. If the system behaves in the same way, then it is time reversal symmetric. In the case of a Hamiltonian, this can be tested by looking at the equations of motion derived from it and seeing if they remain unchanged when time is reversed.

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