Help simple c program with loop, not running through each integer.

[charmedbeauty]

Homework Statement

I want to create a program that prints the sum of integers k for k(1-20)

ie,

k sum
1 1
2 3
3 6
4 10
5 .
6 .
.
.
.
.
.
20 .

in that format

Homework Equations

The Attempt at a Solution

#include <stdio.h>

int main(int argc,char * argv[]){
int i=0, sum=0, n=20;
for (i=0;i<n;++i);{

sum=sum+i;

printf("%d = %4d\n",i, sum);
}

return 0;
}

I don't want the user to enter an input (hence no scanf) I just want the program to run through integers 1-20 and print there sum.

when I run this it just prints 20 = 20??

help please!

Thanks.

 

[jedishrfu]

you put a semicolon in a bad spot

for ( ... ) ;{ ...code block... }

just runs the for loop but not the code block

try this:

for ( ...) { ...code block... }

this is a famous gotcha that many programmers do at one time or another

 

[charmedbeauty]

you put a semicolon in a bad spot

for ( ... ) ;{ ...code block... }

just runs the for loop but not the code block

try this:

for ( ...) { ...code block... }

this is a famous gotcha that many programmers do at one time or another

Ohh wow that worked... I was stuck on that for a while... no pun intended:)

 

[Xitami]

and now try without a loop

 

[rezeew]

Hello,

Thank you for sharing your code and explaining your issue. From what I can see, the problem lies in the placement of your curly braces in the for loop. Currently, your loop is only running the statement inside the curly braces once, as it is acting as the body of the loop. To fix this, you can remove the semicolon after the for loop and move the curly brace down to include the printf statement. This will ensure that the loop runs through each integer and prints the correct sum.

Additionally, I noticed that your initial value for the loop is set to 0, which will result in your first sum being 0 instead of 1. To fix this, you can change the initial value to 1.

Your updated code should look something like this:

#include <stdio.h>

int main(int argc, char *argv[]) {
int i = 1, sum = 0, n = 20;
for (i = 1; i <= n; ++i) {
sum = sum + i;
printf("%d = %d\n", i, sum);
}
return 0;
}

I hope this helps. Keep up the good work with your programming skills!