- #1
b2386
- 35
- 0
Hi all,
Right now I am doing some Diff equations homework but am having difficulty with a problem. The problem asks me to draw a direction field for the system [tex]x' = \left(\begin{array}{cc}1 & 1\\4 & 1\end{array}\right)\left(\begin{array}{cc}x_1\\x_2\end{array}\right)[/tex]
The proper Mathematica function is of the form PlotVectorField[{f(x), f(y)},{x, xmin, xmax}, {y, ymin, ymax}], where f(x) and F(y) are the function in terms of x and y. I understand how to do this for a simple function such as [tex]y' -2y=4-t[/tex]. In this case, f(x) = 1 and f(y) = 2y-t+4. However, the matrices that I am currenly facing make things for difficult. The resulting graph should have axes of x_1 and x_2 but that's all I know for sure. Can anyone help me please?
Right now I am doing some Diff equations homework but am having difficulty with a problem. The problem asks me to draw a direction field for the system [tex]x' = \left(\begin{array}{cc}1 & 1\\4 & 1\end{array}\right)\left(\begin{array}{cc}x_1\\x_2\end{array}\right)[/tex]
The proper Mathematica function is of the form PlotVectorField[{f(x), f(y)},{x, xmin, xmax}, {y, ymin, ymax}], where f(x) and F(y) are the function in terms of x and y. I understand how to do this for a simple function such as [tex]y' -2y=4-t[/tex]. In this case, f(x) = 1 and f(y) = 2y-t+4. However, the matrices that I am currenly facing make things for difficult. The resulting graph should have axes of x_1 and x_2 but that's all I know for sure. Can anyone help me please?