- #1
AlphaLima
- 2
- 0
Homework Statement
A cube of side length 3 cm floats in water (density = 1g/cm^3) with 1 cm floating above the water. What is the density of this cube?
Homework Equations
Fbouyant = ρfluid*g*Vsubmerged
Fg= mg
The Attempt at a Solution
I am having problems figuring out what the submerged volume of the cube is to plug into the formula. I have a formula that states that volume submerged for an object = Az, where A = the area of the object and z = the depth that the object is submerged so:
V=Az = 6(3cm^2) * 2cm (that is submerged) = 108cm^3 It seems that this is wrong though since the volume should be 18cm^3 to give me the right answer.
I then use the formula
Fb = Fg for an object that is floating
ρfluid*g*Vsubmerged = ρobject*g* Vtotal of object
cancelling out the g from both sides gives a ratio that allows me to calculate for the density of the object. The answer is supposed to be 2/3 g/cm^3 which I am not getting.
Any guidance would be appreciated :)