How Does the Angle of Force Application Affect Work Done on a Cart?

In summary, the shopper in a supermarket pushes a cart with a force of 35.0 N at an angle of 25.08 below the horizontal, balancing friction forces to maintain a constant speed. (a) The work done by the shopper on the cart as she moves down a 50.0-m-long aisle is 1586 J. (b) When the shopper goes down the next aisle, pushing horizontally at the same speed, the applied force would be smaller. (c) The work done on the cart by the shopper would also be smaller, as the force is no longer applied at an angle.
  • #1
Zynoakib
70
0

Homework Statement


A shopper in a supermarket pushes a cart with a
force of 35.0 N directed at an angle of 25.08 below
the horizontal. The force is just sufficient to balance
various friction forces, so the cart moves at constant
speed. (a) Find the work done by the shopper
on the cart as she moves down a 50.0-m-long aisle.
(b) The shopper goes down the next aisle, pushing horizontally
and maintaining the same speed as before.
If the friction force doesn’t change, would the shopper’s
applied force be larger, smaller, or the same?
(c) What about the work done on the cart by the
shopper?

I only don't understand (c)

Homework Equations


W = Fd

The Attempt at a Solution


The answer for (c) is "the same" (as the answer of (a) which is 1586N). I understand since the car travels the same distance, the work done by force should be the same as (a), but if I use W = Fd to calculate (c), it should be W = (35)(50) which is not the same as (a). So, why is that?

Thanks!
 
Physics news on Phys.org
  • #2
For (c), the force done on the cart is not equal to 35 anymore. The speed of the cart is maintained, but not the force. Remember that the force is no longer applied at an angle.
 
  • Like
Likes Zynoakib and senan
  • #3
What did you answer for b?
(Your answer to a has the wrong units.)
 
  • #4
haruspex said:
What did you answer for b?
(Your answer to a has the wrong units.)

smaller

ecastro said:
For (c), the force done on the cart is not equal to 35 anymore. The speed of the cart is maintained, but not the force. Remember that the force is no longer applied at an angle.

Ok, I get it now. Thanks!
 

Related to How Does the Angle of Force Application Affect Work Done on a Cart?

What is work done when pushing a cart?

Work done when pushing a cart refers to the amount of force applied over a distance to move the cart from one point to another.

How is work done calculated?

Work done is calculated by multiplying the force applied in the direction of motion by the distance over which the force is applied.

What factors affect the amount of work done when pushing a cart?

The amount of work done when pushing a cart is affected by the force applied, the distance over which the force is applied, and the weight and friction of the cart.

Does the speed at which the cart is pushed affect the work done?

Yes, the speed at which the cart is pushed affects the work done. The faster the cart is pushed, the more work is done because the distance over which the force is applied increases.

Can work be negative when pushing a cart?

Yes, work can be negative when pushing a cart. This occurs when the force applied is in the opposite direction of the motion of the cart, resulting in work being done against the motion of the cart.

Similar threads

  • Introductory Physics Homework Help
Replies
4
Views
2K
  • Introductory Physics Homework Help
Replies
1
Views
1K
  • Introductory Physics Homework Help
Replies
10
Views
1K
Replies
29
Views
1K
  • Introductory Physics Homework Help
Replies
4
Views
5K
  • Introductory Physics Homework Help
Replies
4
Views
1K
  • Introductory Physics Homework Help
2
Replies
57
Views
3K
  • Introductory Physics Homework Help
2
Replies
58
Views
3K
  • Introductory Physics Homework Help
Replies
8
Views
5K
  • Introductory Physics Homework Help
Replies
6
Views
10K
Back
Top