How much can be lifted with a wheel barrow?

[katamoria]

Homework Statement

suppose that you can lift no more than 450N unaided.
a) how much can you lift using a 2 m long wheel barrow? assume that the wheelbarrow weighs 80N and that its center of gravity is .6m from the wheel. in addition, assume hat the load carried in the wheelbarrow is also .6m from the wheel
b) where does the force come from to enable you to lift more than 450N when you use the wheelbarrow?

Homework Equations

Torque = force x perpendicular distance between the axis and the line of action of the force
sum of torques = Ia

The Attempt at a Solution

I thought I could set the weight lifted equal to forces with the angled lift, but either that's wrong or i don't know how to do it.

 

[mgb_phys]

Think of force * distance for the weight and your lift, both measured from the wheel

 

[kerimek]

I can provide a response to this content by first explaining the principles of torque and the use of a wheelbarrow. Torque is defined as the force applied to an object multiplied by the distance between the axis and the line of action of the force. In the case of a wheelbarrow, the force is applied to the handles and the distance is the length of the wheelbarrow. This creates a lever system, where the center of gravity of the wheelbarrow serves as the fulcrum.

In order to calculate the maximum weight that can be lifted with a wheelbarrow, we must first consider the weight of the wheelbarrow itself. In this case, the wheelbarrow weighs 80N and its center of gravity is located 0.6m from the wheel. This means that the weight of the wheelbarrow creates a torque of 48Nm (80N x 0.6m).

Next, we must consider the weight of the load being carried in the wheelbarrow. The load is also located 0.6m from the wheel, so it creates a torque of 288Nm (480N x 0.6m).

To lift the wheelbarrow, the force must overcome the torque created by the weight of the wheelbarrow and the load. This force is generated by the person pushing down on the handles of the wheelbarrow. The force required to lift the wheelbarrow can be calculated by dividing the sum of the torques by the perpendicular distance between the axis and the line of action of the force. In this case, the perpendicular distance is 2m, so the force required to lift the wheelbarrow is 168N (336Nm / 2m).

To answer the first question, with a 2m long wheelbarrow, you can lift a maximum weight of 480N (80N + 480N) assuming you are able to apply a force of 168N to the handles.

In response to the second question, the force that enables you to lift more than 450N when using a wheelbarrow comes from the principle of leverage. By using a lever system, the force applied to the handles is amplified, allowing you to lift a heavier load than you would be able to lift unaided. This is due to the fact that the perpendicular distance between the axis and the line of action of the force is longer in the case of a