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ME@VT
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Inverting a 130 Vrms, 40-45 kHz Signal??
Hello everyone, I was wondering if anyone might be willing to help me out on a little problem I am having:
I have an amplifier output of 130*sin(f*t), f = [40 - 45 kHz], and I need to run this into two parallel lines such that initially, line 1 carries 130*sin(f*t) and line 2 carries 130*sin(f*t). Next, I need to flip the sign of line 2 such that the signal becomes -130*sin(f*t).
So my question: Can anyone describe a circuit that can take the high voltage and frequency of the amp. output and invert the waveform?
I was looking into using a high voltage op-amp from MSkennedy.com, but it seems they have op-amps that can take enormous supply voltages, but whos input voltages are limited to ~25 V. I am a complete moron when it comes to electronics, so I'm lost here.
Another option would be changing the phase of signal, but I would have to do so in a fashion that is frequency independent, as part of my testing involves altering the frequency of the signal to observe changes in my actuator performance.
Thank you for taking the time to read this, and thank you for any comments you might have in advance.
Devon
Hello everyone, I was wondering if anyone might be willing to help me out on a little problem I am having:
I have an amplifier output of 130*sin(f*t), f = [40 - 45 kHz], and I need to run this into two parallel lines such that initially, line 1 carries 130*sin(f*t) and line 2 carries 130*sin(f*t). Next, I need to flip the sign of line 2 such that the signal becomes -130*sin(f*t).
So my question: Can anyone describe a circuit that can take the high voltage and frequency of the amp. output and invert the waveform?
I was looking into using a high voltage op-amp from MSkennedy.com, but it seems they have op-amps that can take enormous supply voltages, but whos input voltages are limited to ~25 V. I am a complete moron when it comes to electronics, so I'm lost here.
Another option would be changing the phase of signal, but I would have to do so in a fashion that is frequency independent, as part of my testing involves altering the frequency of the signal to observe changes in my actuator performance.
Thank you for taking the time to read this, and thank you for any comments you might have in advance.
Devon