- #1
Hammad Shahid
- 64
- 3
- TL;DR Summary
- I want to draw out the product of the reaction between NH3 and BF3.
In the reaction between NH3 and BF3, the boron will bond with the extra lone pair in NH3. This is only possible if we let Nitrogen stay unhybridized. However, the molecular structure for NH3 is tetrahedral (and is therefore hybridized as sp3) due to distancing the e- pairs.
If we go by this model, however, NH3 has no lone pair to donate to the empty orbital of BF3.
Also, how is it that NH3 contains a lone pair but does not show that in energy diagram. From what I know, if an element has a lone pair, it will be an unhybridized orbital in the energy diagram.
Thanks for any help.
If we go by this model, however, NH3 has no lone pair to donate to the empty orbital of BF3.
Also, how is it that NH3 contains a lone pair but does not show that in energy diagram. From what I know, if an element has a lone pair, it will be an unhybridized orbital in the energy diagram.
Thanks for any help.