Laplace equation in rectengualar channel (Fluid mechanics)

In summary, the problem involves estimating the speed of a potential flow in a rectangle channel with depth h and length l in the y direction. The fluid is incompressible and has a boundary condition of \dfrac{\partial^2 \phi}{t^2} + g\dfrac{\partial \phi}{\partial z} = 0 on the surface z = 0. The equations used for the free surface and ansatz are \nabla^2 \phi = 0, \vec v = \nabla \phi(x,y,z,t), \zeta(x,y,t) = \dfrac{1}{g} \dfrac{\partial \phi}{\partial t}, and \phi = Z
  • #1
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Homework Statement


Estimate the speed a potential flow in gravity field would have in direction [itex] y [/itex] in rectangle channel with depth [itex] h [/iteh] and length [itex] l [/itex]. The fluid is incompressible and on the surface [itex] z = 0 [/itex] we have boundary condition [itex] \dfrac{\partial^2 \phi}{t^2} + g\dfrac{\partial \phi}{\partial z} = 0 [/itex]


Homework Equations


[itex] \nabla^2 \phi = 0, \vec v = \nabla \phi(x,y,z,t), [/itex]
The free surface is described by [itex] \zeta(x,y,t) = \dfrac{1}{g} \dfrac{\partial \phi}{\partial t}[/itex] with the
ansatz [itex] \phi = Z(z) e^{-\omega t}e^{i(k_1x + k_2y)} [/itex] which is for channel with depth [itex] h [/itex] and infinity length.

The Attempt at a Solution



We put the ansatz in Laplace and obtain [itex] Z^{\prime \prime} - \underbrace{(k_1^2 + k_2^2)}_{k}Z = 0[/itex]

The solution is with boundary condition [itex] \nabla \phi (-h) = 0 \Rightarrow \dfrac{d }{d z } Z(-h) = 0 [/itex]

We obtain a solution [itex] \phi( \vec r, t ) = \dfrac{ig}{\omega}A \dfrac{ch(k(z+h))}{ch kh} e^{i(k_1x + k_2y - \omega t)} [/itex]

My problem is how to express the boundary limits on the walls at [itex] (0,-h) \cup (l,-h) [/itex] expanding in the y direction.
 
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  • #2
The solution for the vertical velocity is[itex] \dfrac{\partial \phi}{\partial t} = - \omega \phi = - \dfrac{gAchkh}{ch(k(z+h))}e^{i(k_1x + k_2y - \omega t)} But I am not sure how to express the boundary limits on the walls at [itex] (0,-h) \cup (l,-h) expanding in the y direction.
 

Related to Laplace equation in rectengualar channel (Fluid mechanics)

1. What is Laplace's equation in fluid mechanics?

Laplace's equation in fluid mechanics is a partial differential equation that describes the steady-state behavior of a fluid in a rectangular channel. It relates the rate of change of the fluid's velocity to its pressure and is used to analyze the flow of fluids in various applications.

2. How is Laplace's equation derived for a rectangular channel?

Laplace's equation for a rectangular channel is derived by applying the principles of conservation of mass and momentum to a small control volume within the channel. This results in a set of simplified equations that can be solved to obtain the velocity and pressure distribution within the channel.

3. What are the boundary conditions for solving Laplace's equation in a rectangular channel?

The boundary conditions for Laplace's equation in a rectangular channel include the velocity and pressure at the channel walls, as well as the inlet and outlet conditions. These boundary conditions are necessary to determine the unique solution for the velocity and pressure distribution within the channel.

4. What are the applications of Laplace's equation in fluid mechanics?

Laplace's equation has numerous applications in fluid mechanics, including the analysis of laminar and turbulent flows in pipes, channels, and other geometries. It is also used in the design and optimization of fluid systems, such as pumps, turbines, and heat exchangers.

5. How is Laplace's equation solved in a rectangular channel?

Laplace's equation can be solved analytically using various mathematical techniques, such as separation of variables or the method of images. It can also be solved numerically using computational fluid dynamics (CFD) methods, which involve discretizing the domain and solving the resulting equations using iterative algorithms.

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