- #1
LAHLH
- 409
- 1
Hi,
By analogy with scalar field case, Srednicki leads us to [tex] Z_0 (\eta)=\int \mathcal{D}\Psi \exp{\left[i\int\,\mathrm{d}^4x (\mathcal{L}_0+\eta^{T}\psi)\right]} [/tex] for a Majorana field.
I was expecting something different, like maybe: [tex] Z_0 (\eta)=\int \mathcal{D}\Psi\exp{\left[i\int\,\mathrm{d}^4x (\mathcal{L}_0+\eta^{T}\psi+\eta\psi^{T})\right]} [/tex] at least.
or even: [tex] Z_0 (\eta)=\int \mathcal{D}\Psi \mathcal{D}\bar{\Psi}\ \exp{\left[i\int\,\mathrm{d}^4x (\mathcal{L}_0+\bar{\eta}\psi+\eta\bar{\psi})\right]} [/tex] (why a transpose on eta now and not a bar?)
I mean how would derive VEV's of a a product of barred and unbarred fields like [tex] \langle 0|T\Psi_{\alpha}(x)\bar{\Psi}_{\beta}(y)|0\rangle [/tex] as he computes at the end of ch42, with the above.
Thanks
By analogy with scalar field case, Srednicki leads us to [tex] Z_0 (\eta)=\int \mathcal{D}\Psi \exp{\left[i\int\,\mathrm{d}^4x (\mathcal{L}_0+\eta^{T}\psi)\right]} [/tex] for a Majorana field.
I was expecting something different, like maybe: [tex] Z_0 (\eta)=\int \mathcal{D}\Psi\exp{\left[i\int\,\mathrm{d}^4x (\mathcal{L}_0+\eta^{T}\psi+\eta\psi^{T})\right]} [/tex] at least.
or even: [tex] Z_0 (\eta)=\int \mathcal{D}\Psi \mathcal{D}\bar{\Psi}\ \exp{\left[i\int\,\mathrm{d}^4x (\mathcal{L}_0+\bar{\eta}\psi+\eta\bar{\psi})\right]} [/tex] (why a transpose on eta now and not a bar?)
I mean how would derive VEV's of a a product of barred and unbarred fields like [tex] \langle 0|T\Psi_{\alpha}(x)\bar{\Psi}_{\beta}(y)|0\rangle [/tex] as he computes at the end of ch42, with the above.
Thanks
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