- #1
Gregory.gags
- 31
- 2
An Earthquake measures 6.1 on the Richter Scale. What is the rating on an earthquake that is twice as powerful?
I = I0 × 10M
I-intensity of earthquake
I0-earthquake with intensity of 0
M-magnitude of earthquake on the Richter Scale
So I figured I'd use I1 = I0 × 106.1 to find the intensity of earthquake 1 (I1)
then, 2I=I2 to find the intensity of earthquake 2 (I2), which is double that of I1
and finally, M=log(I2/I0) to find the resulting magnitude, or rating, of the Richter Scale.
But my problem begins at the very beginning.
If I0 = 0 then I1 = 0 too...
and I'm quite thrown off by this.
Am I taking the totally wrong approach to this?
I = I0 × 10M
I-intensity of earthquake
I0-earthquake with intensity of 0
M-magnitude of earthquake on the Richter Scale
So I figured I'd use I1 = I0 × 106.1 to find the intensity of earthquake 1 (I1)
then, 2I=I2 to find the intensity of earthquake 2 (I2), which is double that of I1
and finally, M=log(I2/I0) to find the resulting magnitude, or rating, of the Richter Scale.
But my problem begins at the very beginning.
If I0 = 0 then I1 = 0 too...
and I'm quite thrown off by this.
Am I taking the totally wrong approach to this?