Nodal Analysis problem with voltage sources

In summary, you are being asked to use the voltages at each node to calculate the individual currents for nodes 2 and 4, and then show that the sum of all currents entering and leaving each node is equal to zero, thereby demonstrating Kirchhoff's Current Law.
  • #1
speakas
10
0

Homework Statement



I have a circuit and I need to find the Nodal Equations that would mathematically describe the circuit, then proceed to finding the voltages at each node using Cramers rule and the currents at nodes 2 and 4. I don't think I would have much of a problem utilising Cramers rule. The problem I have right now is deriving the Nodal Equations.
However I would love to have the rest of my methods validated since I am simply unsure if I am on the right track or not

HPc33vW.png

Homework Equations


The Attempt at a Solution



I am quite sure I have many errors in my attempted solution at deriving equations to describe the circuit. I am unsure what to do with the voltages sources.

946705_10151852006080349_788668334_n.jpg
Please find the diagram of the circuit and my attempt at solving the problem in the attached files.

Thank you very much in advance!
 
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  • #2
The 12V battery fixes the potential between your nodes 1 and 2, so they don't constitute independent essential nodes. In fact, the two taken together comprise a "supernode".

attachment.php?attachmentid=61983&stc=1&d=1379608117.gif


Keep only one variable to describe the potential for the supernode (V1 or V2) and write a single node equation. Suppose you keep V2 as the variable for the supernode, then the potential at the former node 1 connections would be "V2+12".
 

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  • #3
So I take the super node and consider it as a combined node consisting of node 1 and node 2?

Here is my new system of equations and the voltages I got from each node
1239056_10151860892230349_1598127066_n.jpg



I am unsure if it correct or not as the values I calculated for V3 do not seem to be very attractive.
 
  • #4
I realized I made a mistake at node 3, It should be -V1/10.

Anyways here are the new voltages I came up withV1 = 8.214
V2 =-3.7857
V3 = 6.57
V4 = 4.4
 
  • #5
I am completely unsure on how I can find the current at node 2 and 4 and show KCL holds for each though...

Do I just find the nodal equation for node 2 and node 4 and find the current using the voltages that I have already derived earlier to find the total current in each node?
 
  • #6
speakas said:
I realized I made a mistake at node 3, It should be -V1/10.
Yup, I spotted that and was going to mention it when I thought I'd check this later post :smile:
Your equations, with that update, now look perfect.
Anyways here are the new voltages I came up with


V1 = 8.214
V2 =-3.7857
V3 = 6.57
V4 = 4.4
Strangely enough, your previous set of numbers look closer to what I'm getting... Must be some slips creeping into the mechanics of solving the equations. Are you using Cramer's Rule or just substitutions?
 
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  • #7
gneill said:
Yup, I spotted that and was going to mention it when I thought I'd check this later post :smile:
Your equations, with that update, now look perfect.

Strangely enough, your previous set of numbers look closer to what I'm getting... Must be some slips creeping into the mechanics of solving the equations. Are you using Cramer's Rule or just substitutions?

I was using cramers rule. I did spot another error that I made. I forgot to multiply the 2 by 4 when trying to eliminate the denominators to form the matrice.

So anyways here are my new set of solutions which I believe look much better

V1= 7.14 or 50/7
V2= -4.857 or -34/7
V3= 4.734 or 232/49
V4= 0.476 or 10/21
 
  • #8
speakas said:
I was using cramers rule. I did spot another error that I made. I forgot to multiply the 2 by 4 when trying to eliminate the denominators to form the matrice.

So anyways here are my new set of solutions which I believe look much better

V1= 7.14 or 50/7
V2= -4.857 or -34/7
V3= 4.734 or 232/49
V4= 0.476 or 10/21

Much better indeed! :approve:
 
  • #9
Thank you very much for your time and help!

Unfortunately I still have another question
"Using the voltages at each node calculate the current for nodes 2 & 4 and show Kirchhoff’s Current Law (KCL) holds for each of these nodes."

I think I am mostly having trouble interpreting this question but if I am not mistaken I am just subbing the values V1-V4 obtained back into the equations found at the nodes? If this is the case I am unsure how I can attempt to solve for Node 2.

Thanks again!
 
  • #10
speakas said:
Thank you very much for your time and help!
I'm happy to help!
Unfortunately I still have another question
"Using the voltages at each node calculate the current for nodes 2 & 4 and show Kirchhoff’s Current Law (KCL) holds for each of these nodes."

I think I am mostly having trouble interpreting this question but if I am not mistaken I am just subbing the values V1-V4 obtained back into the equations found at the nodes? If this is the case I am unsure how I can attempt to solve for Node 2.
Yes, you'll use the voltage values that you obtained for the nodes and plug them into the appropriate terms of the node equations to find the individual current values.

I agree that node 2 is a bit trickier since there's no explicit term in your equations corresponding to the current through the battery. However, if you consider the supernode as a whole, the current through its "battery leg" can be found using KCL. Does that make sense?
 
  • #11
node.jpg


So for Node 4 I am just essentially showing that the currents through the resistors entering the node is equal to the current found at the current source.

As for node 2, I am showing that the current at the battery leg connected to node 2 is equal to the currents through the resistors connected to node 2?
 
  • #12
speakas said:
View attachment 62094

So for Node 4 I am just essentially showing that the currents through the resistors entering the node is equal to the current found at the current source.
Sure. The idea being to show that the sum of all currents entering and leaving a given node is zero.
As for node 2, I am showing that the current at the battery leg connected to node 2 is equal to the currents through the resistors connected to node 2?

Take a step back from node 2 to begin with and find the current in the battery leg first. To do that, consider the supernode as a whole. It has a total of four connections to the rest of the network, one of which is that battery leg. KCL to find the battery current.

Then use that battery current to show that it satisfies the KCL requirement for your node 2 equation.

Really, this part of the problem is a bit sneaky since while it seems at first glance to be a small task involving four currents, it actually forces you to calculate a lot more currents than just those at node 2!
 
  • #13
yeah...ok you lost me there :S.

I can't figure out which is the four connections?
 
  • #14
speakas said:
yeah...ok you lost me there :S.

I can't figure out which is the four connections?

Oops. My bad. I'd forgotten that node 2 is actually part of the supernode! :blushing:

Consider instead node 1 alone. It has the four connections you need to consider.
 
  • #15
Another way to deal with voltages sources without considering "supernodes", is to use Modified Nodal Analysis:

http://www.swarthmore.edu/NatSci/ech.../mna/MNA2.html

MNA will give the current through the voltage source directly. For your problem, the MNA formulation in matrix form would be, with the source current denoted IE:

attachment.php?attachmentid=62104&d=1379965283.png


Solving the system, we get:

attachment.php?attachmentid=62105&d=1379965354.png


The current in the source is 149/18375 amps.
 

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  • #16
The Electrician said:
Another way to deal with voltages sources without considering "supernodes", is to use Modified Nodal Analysis:

http://www.swarthmore.edu/NatSci/ech.../mna/MNA2.html

MNA will give the current through the voltage source directly. For your problem, the MNA formulation in matrix form would be, with the source current denoted IE:

attachment.php?attachmentid=62104&d=1379965283.png


Solving the system, we get:

attachment.php?attachmentid=62105&d=1379965354.png


The current in the source is 149/18375 amps.


I would use MNA but a 5x5 matrice is not very attractive...
 
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  • #17
gneill said:
Oops. My bad. I'd forgotten that node 2 is actually part of the supernode! :blushing:

Consider instead node 1 alone. It has the four connections you need to consider.


If I were to just consider those 4 connections, wouldn't that mean the current would just be the minus of what I obtained in my solution? or should the values be the one posted using the MNA method?
 
  • #18
Without using MNA, you could get the current in the source by knowing the current in R1, R4 and R6. Then you will have all the currents at node 2, which you can show all sum to zero.

You already got all the node voltages in post #7; I only showed the MNA solution as an example of an alternate method to get the current in the source directly.
 

Related to Nodal Analysis problem with voltage sources

1. What is nodal analysis?

Nodal analysis is a method used to solve electrical circuits, specifically those with multiple voltage sources and resistors. It involves identifying and analyzing the voltages at specific nodes (points) in the circuit.

2. How does nodal analysis work?

Nodal analysis works by applying Kirchhoff's Current Law (KCL) at each node in the circuit. This law states that the sum of currents entering a node must equal the sum of currents leaving the node. By setting up a system of equations using KCL, the unknown node voltages can be solved.

3. What are the advantages of using nodal analysis?

Nodal analysis is a systematic and efficient method for solving complex electrical circuits. It can handle circuits with multiple voltage sources and resistors, and it can also be easily adapted to include current sources and dependent sources. Moreover, nodal analysis provides a clear understanding of how current flows through a circuit.

4. What are the limitations of nodal analysis?

Nodal analysis can only be used for circuits that can be represented by a network of nodes and branches. It also assumes that the circuit is in steady state, meaning that all voltages and currents are constant. Additionally, nodal analysis can become complicated for circuits with a large number of nodes.

5. Are there any tips for solving nodal analysis problems?

Yes, here are a few tips for solving nodal analysis problems:
- Start by labeling all the nodes in the circuit.
- Choose a reference node (usually the one with the most connections) and assign it a voltage of 0.
- Apply KCL at each of the remaining nodes to create a system of equations.
- Solve the system of equations to find the node voltages.
- Double check your solution by making sure that KCL is satisfied at each node.
- Practice, practice, practice!

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