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sadaronjiggasha
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In classical physics we know photon emits when electron move from higher to lower state but in nuclear fusion photon emits when neutron turn into proton. Is both correct?
No. Your comment about an electron and photon is correct, but when a neutron decays into a proton (beta decay) a down quark in the neutron decays into an up quark. As the charge of the quarks are different this cannot be mediated by a (chargeless) photon. In fact, the beta decay process is ##d \to W^- + u \to e^- + \overline{ \nu } _e + u##. The d emits a ##W^-## rather than a photon.sadaronjiggasha said:In classical physics we know photon emits when electron move from higher to lower state but in nuclear fusion photon emits when neutron turn into proton. Is both correct?
You cannot understand physics by watching videos.sadaronjiggasha said:I found the fusion thing in a video where they describing how sun emits light to earth.
The photons produced by fusion in the centre of a star pass energy to the outside over a period of thousands of years. You can’t regard the photons radiated in our direction as ‘the same’ as what’ produced inside.sadaronjiggasha said:I found the fusion thing in a video where they describing how sun emits light to earth.
Which is incorrect. You get a proton, an electron, and an (anti)neutrino.sadaronjiggasha said:"neutron decaying into a proton does not produce a photon; you get the neutron, a positron, and a neutrino
So you start with a neutron and end up with a neutron plus other stuff? Good luck with that.sadaronjiggasha said:neutron decaying into a proton does not produce a photon; you get the neutron, a positron, and a neutrino
But wait, so you're saying that the "excellent scientist" found by @sadaronjiggasha to answer his questions is not so excellent?Vanadium 50 said:Which is incorrect. You get a proton, an electron, and an (anti)neutrino.
To be precise, the neutron decays into a proton and a ##W^-## and the ##W^-## then decays into an electron and an electron anti-neutrino. As to the rest, yes, the fusion reactions are what create the photons that eventually escape from the Sun.sadaronjiggasha said:Ok I got my answer from another excellent scientist who help me to clear my doubt. I am sharing here it may help others. "neutron decaying into a proton does not produce a photon; you get the neutron, a positron, and a neutrino. Fusion reactions, though, can involve excited nuclei and nuclear de-excitations can produce photons. Also particle-antiparticle annihilations, as well as acceleration of charged particles, in addition to the electron (atomic) transition."
The gamma photons are not the same ones that escape as a range of photons radiated from the surface. These are largely around optical frequencies and arise after many many interactions on the way through.topsquark said:To be precise, the neutron decays into a proton and a ##W^-## and the ##W^-## then decays into an electron and an electron anti-neutrino. As to the rest, yes, the fusion reactions are what create the photons that eventually escape from the Sun.
-Dan
Photon emission is the process by which a photon, or a particle of light, is released from an atom or molecule. This can occur through various mechanisms, such as when an electron in an excited state returns to a lower energy state, or during nuclear reactions.
Classical fusion refers to the fusion of atoms at high temperatures and pressures, such as in the core of the sun, where hydrogen atoms combine to form helium. Nuclear fusion, on the other hand, involves the fusion of atomic nuclei, which releases a significant amount of energy.
In classical fusion, photon emission occurs as a result of the fusion process itself, as the energy released during fusion causes electrons to jump to lower energy levels and emit photons. In nuclear fusion, photon emission can also occur as a byproduct of the reaction, but it is not the primary source of energy.
Yes, photon emission can be controlled to some extent in nuclear fusion reactions. Scientists are currently working on developing methods to control the release of photons in order to harness the energy produced by nuclear fusion for practical use.
The primary application of photon emission in nuclear fusion is the production of energy. If harnessed effectively, nuclear fusion could provide a nearly limitless source of clean energy, with minimal impact on the environment. Photon emission can also be used for diagnostic purposes in studying and understanding the fusion process.