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anOldMan
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[SOLVED] Physics 11 Speed and acceleraton
The brakes on a car permit it to decelerate at the rate of -8.0m/s^2. How much distance is required to stop this car when it is traveling 60.0km/hr?
The answer given is 173.6m
A=V/T
D=RT
I solved it this way
60km/h = 16.667m/s
A=V/T 16.667m/s / -.80m/s^2 = 20.834 seconds
D=RT 16.667m/s x 20.834seconds = 347.24m
This is wrong and I do not understand why. Am I doing it right or is the answer wrong?
Homework Statement
The brakes on a car permit it to decelerate at the rate of -8.0m/s^2. How much distance is required to stop this car when it is traveling 60.0km/hr?
The answer given is 173.6m
Homework Equations
A=V/T
D=RT
The Attempt at a Solution
I solved it this way
60km/h = 16.667m/s
A=V/T 16.667m/s / -.80m/s^2 = 20.834 seconds
D=RT 16.667m/s x 20.834seconds = 347.24m
This is wrong and I do not understand why. Am I doing it right or is the answer wrong?