Poisson, relativists toolkit, problem 1.3: Timelike geodesic parametrised by a non-affine parameter

  • #1
Gleeson
30
4
Homework Statement
(a) Let ##x^a(\lambda)## describe a timelike geodesic parametrised by a non-affine parameter ##\lambda##, and let ##t^a = \frac{dx^a}{d \lambda}## be the geodesic's tangent vector. Calculate how ##\epsilon := -t_at^a## changes as a function of ##\lambda##.

(b) Let ##\xi^a## be a killing vector. Calculate how ##p := \xi_at^a## changes as a function of lambda on that same geodesic.


(c) Let ##v^a## be such that in a spacetime with metric ##g_{ab}##, ##Lie_vg_{ab} = 2cg_{ab}##, where c is a constant. (Such a vector is called homothetic.) Let ##x^a(\tau)## describe a timelike geodesic parametrised by proper time ##\tau##, and let ##u^a = \frac{d x^a}{d \tau}## be the four-velocity. Calculate how ##q = v_a u^a## changes with ##\tau##.
Relevant Equations
As above
For (a) and (b), since the geodesic is not affinely parametrised, we have that ##t^a\nabla_a t^b = f(\lambda) t^b##, for some function f.

As a results, for (a) I get that ##t^a \nabla_a \epsilon = 2 f(\lambda) \epsilon##. And for (b) I get that ##t^a \nabla_a p = f(\lambda) p##. (I can write out why I got those answers if needed.)

My suspicion is that I am doing something wrong, since I think it is strange to need to give the answer in terms of some unknown function that I introduced.

I'd appreciate some assistance please.
 

Similar threads

Replies
13
Views
689
  • Special and General Relativity
Replies
10
Views
1K
  • Calculus and Beyond Homework Help
Replies
1
Views
866
  • Special and General Relativity
Replies
16
Views
7K
  • Special and General Relativity
Replies
10
Views
4K
  • Advanced Physics Homework Help
Replies
2
Views
3K
  • Advanced Physics Homework Help
Replies
1
Views
1K
  • Special and General Relativity
Replies
11
Views
256
  • Calculus and Beyond Homework Help
Replies
1
Views
1K
  • Advanced Physics Homework Help
Replies
5
Views
2K
Back
Top