- #1
perplexabot
Gold Member
- 329
- 5
Hey all, I was wondering if you can help me define the arguments for the dare() function of matlab. Here is the DARE form I have:
[tex]
\begin{equation}
\begin{split}
\Phi(p_\infty) &= \Phi_\infty = \Phi_{33}-\Phi_{32}(\Phi_\infty+\Phi_{R})^{-1}\Phi_{23}\\
&=\Phi_{33}+\Phi_{32}\Phi_{R}^{-1}\Phi_\infty\Phi_{R}^{-1}\Phi_{23}-\Phi_{32}\Phi_{R}^{-1}\Phi_\infty(\Phi_\infty+\Phi_{R})^{-1}\Phi_\infty\Phi_{R}^{-1}\Phi_{23}-\Phi_{32}\Phi_{R}^{-1}\Phi_{23}
\end{split}
\end{equation}
[/tex]
Here is how MATLAB's dare() function works.
Here is how I defined my variables: [itex]E = I[/itex], [itex]B = I[/itex], [itex]R = \Phi_R[/itex], [itex]Q = \Phi_{33}[/itex], [itex]S=\Phi_{32}[/itex], , [itex]A = 2\Phi_R^{-1}S^T[/itex].
Is this correct?
Thank you : )
PS: Please let me know if this thread belongs elsewhere, as I would like to maximize feedback from the PF community.
[tex]
\begin{equation}
\begin{split}
\Phi(p_\infty) &= \Phi_\infty = \Phi_{33}-\Phi_{32}(\Phi_\infty+\Phi_{R})^{-1}\Phi_{23}\\
&=\Phi_{33}+\Phi_{32}\Phi_{R}^{-1}\Phi_\infty\Phi_{R}^{-1}\Phi_{23}-\Phi_{32}\Phi_{R}^{-1}\Phi_\infty(\Phi_\infty+\Phi_{R})^{-1}\Phi_\infty\Phi_{R}^{-1}\Phi_{23}-\Phi_{32}\Phi_{R}^{-1}\Phi_{23}
\end{split}
\end{equation}
[/tex]
Here is how MATLAB's dare() function works.
Here is how I defined my variables: [itex]E = I[/itex], [itex]B = I[/itex], [itex]R = \Phi_R[/itex], [itex]Q = \Phi_{33}[/itex], [itex]S=\Phi_{32}[/itex], , [itex]A = 2\Phi_R^{-1}S^T[/itex].
Is this correct?
Thank you : )
PS: Please let me know if this thread belongs elsewhere, as I would like to maximize feedback from the PF community.