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Homework Statement
Collar A starts from rest at t=0 and moves upward with a constant accleration of 9cms^-2. Knowing that collar B moves downward with a constant velocity of 45.7cms^-1, determine the time at which the velocity of block c is zero and the corresponding position of block c
Homework Equations
Xa + Xb + Xc = constant
dXa/dt + dXb/dt + dXc/dt = 0
Va + Vb + Vc = 0
dVa/dt + dVb/dt + dVc/dt = 0
Aa + Ab + Ac = 0
Aa = 9cms^-2 constant
Va = 9t cms^-1
Xa = 4.5t^2 + Xao cm
Ab = 0
Vb = -45.7cms^-1
Xb = -45.7t + Xbo cm
The Attempt at a Solution
At first I thought that 9t - 45.7 = 0 is the equation to find the time t when the velocity of block C is 0, but the picture confused me as it shows like when B goes down , block C will go up and when A goes up block C will go up as well, so the block will keep going up, won't it be like that? and even if i found out the time t, the position of block C can not be found as the initial positions of A, B, and C are unclear.
Help me please TT