- #1
James Brady
- 105
- 4
As 2 time pieces are moving relative to each other in a non accelerated reference frame, they will both see the other as slow. As time goes on, the amount of observed error in the other clock will continue to grow greater and greater. Let's say that after a while both clocks are 10 hours ahead of the other according to itself.
Now what happens when the two time pieces enter the same reference frame? What happens to this 10 hours of observed error? I understand the ticking rate will be synchronized, but will the times displayed by the arms on the clock face be the same as well.
This scenario was set up to be perfectly symetrical. So when entering each other's reference frame, they both accelerate an equal amount to do so.
I appreciate any help in clarifying this matter.
Now what happens when the two time pieces enter the same reference frame? What happens to this 10 hours of observed error? I understand the ticking rate will be synchronized, but will the times displayed by the arms on the clock face be the same as well.
This scenario was set up to be perfectly symetrical. So when entering each other's reference frame, they both accelerate an equal amount to do so.
I appreciate any help in clarifying this matter.