Recent content by kuruman

Assume that the initial separation is L. Can you find an expression for the time of the collision? Can you find the distance the bee has covered in that time? Clearly, the answer is a number times L. I don't know what you mean by "general equation." d = vt is general enough.

I never said that. I said that the object by itself CANNOT have potential energy, so it cannot gain or lose potential energy. It can only have kinetic energy. It's the two-component system of (Earth + object) that can have potential energy which depends on the distance of the object from the...

You seem to be unclear about what your system is. It could be one of 1. Just the object 2. The object and the Earth Specifically, if your system is just the object, it cannot have potential energy no matter what you read in textbooks or on the web. Potential energy needs at least two...

From here "We" are doing work ##W_{we}=+mgh##, gravity is doing work ##W_g=-mgh##, the total work done on the object is zero, the change in kinetic energy is zero and the work energy theorem is satisfied. The negative of the work done by the conservative force of gravity is the change in...

Here is what I think. The axis of rotation of a rigid body is a straight line consisting of all points that are fixed in space relative to a non-rotating inertial frame, while the rest of the points rotate with angular velocity ##\vec {\omega}## about it. In the picture on the right the...

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An equivalent way to see it is in the moving frame of the disc. When the disc is moving with constant velocity ##\mathbf v## relative to the lab frame in which the magnetic field is at rest, the relativistic field transformation equations say that in the rest frame of the disc there is only a...

Now that I'm rethinking all this I'm probably wrong because I'm double counting the Lorentz force. However, it bugs me that the force balance ##qvB=qE\implies E=vB## says that the rod in free fall has increasing velocity which means increasing magnetic force which means increasing electric...

I have a different point of view because I cannot imagine a conductor falling in a magnetic field without reaching terminal velocity because of magnetic braking. For simplicity, I considered a rod of length ##L## equal to the thickness of the disc and oriented parallel to the axis of the disc...

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It's a good thing that he didn't request an abacus . . .

I think that OP's question was adequately answered in post #2. In my opinion it lost its focus because of OP's whataboutism.

That works. In the limit that the inner radius of the shell is equal to the outer radius, then we have a shell of zero thickness which means "no shell at all" in which case the potential and electric field everywhere in space will be that of the point charge. OP seems to think that in the...

So she lived in a flat?

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