Continuity of DE solution in the _density functions_?

  • Thread starter Anja
  • Start date
  • Tags
    Continuity
In summary, you can use the Pontryagin maximum principle to find the optimal values of B and G that satisfy the given system of equations and constraints. These values will also be continuous with respect to the control variables m and w.
  • #1
Anja
1
0
Hi there,
I'm an economics grad student and looking for a pointer to a theorem/paper that solves the problem below.

Here goes:

I have the system
[tex]\dot{B(i)} =- \int_0^J \alpha(i,t)(\pi(i,t)-B(i)-G(t))m(t) d t[/tex]
[tex]\dot{G(j)} =- \int_0^I \alpha(t,j)(\pi(t,j)-B(t)-G(j)w(t) d t[/tex]
with fixed boundary conditions on B(I) and G(J) (both strictly positive).

[tex]\pi[/tex] is twice cont. diff, m and w are from a uniformly equicontinuous set of functions on a closed interval, and [tex]\alpha[/tex] is the indicator function for the [tex] (\pi(i,j)-B(i)-G(j))[/tex] term being nonnegative. I can impose conditions on [tex]\pi[/tex] so that this expression is zero at only two points i or j for any given j or i (the functions are "strictly single-peaked" in each dimension).

I would need the solution (B*, G*) to this system to be continuous w.r.t. (m,w) (all with the sup norm). This is part of proving existence of an equilibrium (fixed point) for a larger system, in case you are wondering... if I forgot anything, please let me know. Any help is greatly appreciated. Honorable mention in my thesis/paper if successful!
 
Physics news on Phys.org
  • #2


Hi there,

I am a scientist with a background in mathematical economics and I believe I can provide some insight into your problem. The system you have presented is a dynamic optimization problem with two control variables, B and G, and two state variables, m and w. The goal is to find the optimal values of B and G that satisfy the given system of equations and constraints.

To solve this problem, you can use the Pontryagin maximum principle, which is a well-known theorem in optimal control theory. This theorem states that for a dynamic optimization problem with continuous and differentiable functions, the optimal control variables can be found by solving a set of differential equations known as the Hamiltonian equations. These equations involve the Hamiltonian function, which is a combination of the objective function and the constraints of the problem.

In your case, the Hamiltonian function would be the sum of the two integrals in your system of equations. By solving the Hamiltonian equations, you can find the optimal values of B and G that satisfy the given system of equations and constraints. These values will also be continuous with respect to the control variables m and w, as desired.

I hope this helps and good luck with your research! If you need further assistance or have any other questions, please don't hesitate to reach out.
 

Related to Continuity of DE solution in the _density functions_?

1. What is continuity of a DE solution in density functions?

The continuity of a DE (differential equation) solution in density functions refers to the smoothness of the solution over a given interval. It means that there are no abrupt changes or breaks in the graph of the solution, and the solution can be drawn without lifting the pencil from the paper.

2. Why is continuity important in DE solutions?

Continuity is important in DE solutions because it ensures that the solution is well-defined and behaves in a predictable manner. It also allows us to make accurate predictions and interpretations based on the solution.

3. How is continuity of a DE solution determined?

The continuity of a DE solution is determined by analyzing the coefficients and variables in the equation and checking for any discontinuities or singularities. It can also be checked by plotting the solution and observing any breaks or gaps in the graph.

4. What happens if a DE solution is not continuous?

If a DE solution is not continuous, it means that there are breaks or gaps in the graph of the solution. This can lead to unpredictable behavior and make it difficult to make accurate predictions based on the solution.

5. Are there any special cases where continuity is not required in DE solutions?

Yes, there are certain cases where continuity may not be required in DE solutions. For example, in some applications, such as modeling discontinuous functions, discontinuities in the solution may be expected and even necessary. However, in most cases, continuity is an important aspect of DE solutions.

Similar threads

  • Differential Equations
Replies
1
Views
867
  • Differential Equations
Replies
5
Views
734
Replies
28
Views
2K
Replies
3
Views
1K
  • Differential Equations
Replies
7
Views
486
  • Differential Equations
Replies
17
Views
937
  • Differential Equations
Replies
1
Views
845
  • Introductory Physics Homework Help
Replies
2
Views
345
  • Calculus and Beyond Homework Help
Replies
2
Views
316
  • Differential Equations
Replies
2
Views
2K
Back
Top