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newjerseyrunner
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If there is a large mass near a black hole, is the event horizon teardrop shaped? Today I was thinking if it was possible to violate the idea that anything that passes the event horizon is gone forever. I forgot to label my picture, Figure 1 is the top and Figure 2 is the bottom.
I imagine a black hole being approached by a massive hypervelocity star, it's nearing it's breaking point because of the tidal forces, but still in one piece. My thought experiment involved taking a trip on a neutrino that is ejected by the star traveling at nearly the speed of light and enters the black hole at an extremely shallow angle.
The neutrino goes into a spiral path inwards, making one full "orbit" around on the inside. Normally in a black hole, it'll never be closer to the event horizon in the future as it is in the present. [Figure 1] But if there is a large object near it, the gravity of the other object should pull on objects close to the event horizon, wouldn't that cancel out a small part of the gravity of the singularity and allow the neutrino to pop back out? Like how when an asteroid slingshots around the Earth and the gravity from the Moon pulls it away? [Figure 2]
If the event horizon gets pushed back towards the singularity on the side of it closest to the star because of the star's gravity, then on the opposite side, where the gravity of both the star and the black hole are acting, the event horizon should be stretched out. So imagine a relativistic proton approaching the black hole, but if the larger star were not there, is not on a collision course with the event horizon, it'll be ejected, but it passes extremely close to it. [Figure 1] With that more massive star there, it would pass the event horizon, could it make half an "orbit" and come out the other side where the event horizon has been pushed back? [Figure 2]
I know this is classical physics, but since everything is in the same reference frame, I'm thinking that that's ok? If any of this is true, would that also imply that if the black hole has a big object orbiting every close to it, would there be Lagrangian points inside the black hole?
I imagine a black hole being approached by a massive hypervelocity star, it's nearing it's breaking point because of the tidal forces, but still in one piece. My thought experiment involved taking a trip on a neutrino that is ejected by the star traveling at nearly the speed of light and enters the black hole at an extremely shallow angle.
The neutrino goes into a spiral path inwards, making one full "orbit" around on the inside. Normally in a black hole, it'll never be closer to the event horizon in the future as it is in the present. [Figure 1] But if there is a large object near it, the gravity of the other object should pull on objects close to the event horizon, wouldn't that cancel out a small part of the gravity of the singularity and allow the neutrino to pop back out? Like how when an asteroid slingshots around the Earth and the gravity from the Moon pulls it away? [Figure 2]
If the event horizon gets pushed back towards the singularity on the side of it closest to the star because of the star's gravity, then on the opposite side, where the gravity of both the star and the black hole are acting, the event horizon should be stretched out. So imagine a relativistic proton approaching the black hole, but if the larger star were not there, is not on a collision course with the event horizon, it'll be ejected, but it passes extremely close to it. [Figure 1] With that more massive star there, it would pass the event horizon, could it make half an "orbit" and come out the other side where the event horizon has been pushed back? [Figure 2]
I know this is classical physics, but since everything is in the same reference frame, I'm thinking that that's ok? If any of this is true, would that also imply that if the black hole has a big object orbiting every close to it, would there be Lagrangian points inside the black hole?
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