- #1
Josh chips
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- Homework Statement
- A stone is dropped from a point 320 meters above the ground; at the same instant another stone is thrown upward from a point 100 meters below the first. I f the two stones strike the ground simultaneously, what is the initial velocity of the second stone.
- Relevant Equations
- y=ut +1/2at^2
since the question states they hit the ground at the same time i firs find the time they hit the ground
y= ut + 1/2at^2 initial velocity is 0 for the first stone
320= 0 + 4.9t^2 this
t= 8 secs
since the 2nd stone was thrown 100 m below stone 1
distance from ground is 220m
220 = ut - 1/2at^2
220= 8u- 4.9*8^2
this give initial velocity as 66.7 m/s but am not sure if its the correct answer need some help
y= ut + 1/2at^2 initial velocity is 0 for the first stone
320= 0 + 4.9t^2 this
t= 8 secs
since the 2nd stone was thrown 100 m below stone 1
distance from ground is 220m
220 = ut - 1/2at^2
220= 8u- 4.9*8^2
this give initial velocity as 66.7 m/s but am not sure if its the correct answer need some help