- #1
leehufford
- 98
- 1
Hello,
I am approaching the end of my multivariable/ vector analysis "Calc III" class and have a question about flux.
My book states that flux, ∫∫ F [itex]\bullet[/itex] N dS measures the fluid flow "across" a surface S per unit time.
Now, the divergence theorem ∫∫∫ divF dV measures the "same thing" but fluid flow THROUGH a solid. How can fluid flow over a surface and through a solid be equated for the same regoin? Is it actually fluid flow THROUGH a surface and not OVER it? That would make more sense.
Hopefully some people who are further along in their math journey can explain this for me. Thanks in advance,
Lee
I am approaching the end of my multivariable/ vector analysis "Calc III" class and have a question about flux.
My book states that flux, ∫∫ F [itex]\bullet[/itex] N dS measures the fluid flow "across" a surface S per unit time.
Now, the divergence theorem ∫∫∫ divF dV measures the "same thing" but fluid flow THROUGH a solid. How can fluid flow over a surface and through a solid be equated for the same regoin? Is it actually fluid flow THROUGH a surface and not OVER it? That would make more sense.
Hopefully some people who are further along in their math journey can explain this for me. Thanks in advance,
Lee