- #1
zzinfinity said:Homework Statement
Number 3 in the attached file
Homework Equations
Not sure
The Attempt at a Solution
Been staring at it for about an hour now and still don't have a clue. Can someone point me in the right direction? Thanks.
zzinfinity said:1. Sorry, I forgot to attach the file. Here it is .
2. Be nice berkeman. I showed a lot of effort. I tried my change of base formula modeling it in MATLAB and all sorts of other things. Just nothing yielded results worth noting here. I just need a hint.
zzinfinity said:1. Sorry, I forgot to attach the file. Here it is .
2. Be nice berkeman. I showed a lot of effort. I tried my change of base formula modeling it in MATLAB and all sorts of other things. Just nothing yielded results worth noting here. I just need a hint.
zzinfinity said:Thanks Dick, that was helpful! I was trying to change the bases to all be in terms of a but I like you idea of using natural log. I changed base of the first three using the equation,
logd(x)= ln(x)/ln(d). I then multiplied the first three terms and, after canceling every thing was left with ln(2a+3)/ln(2a).
Then for the last term ( the one with "b" in it) I changed the base to e and got ln(2b)/ln(2b-1). I pulled my exponents to the front on both my fractions and multiplied
ln(2a+3)/(a*ln(2)) * (bln(2)/ln(2b-1)). I canceled my ln(2) terms and was left with
What's
b*ln(2a+3)/(a*ln(2b-1)
Can you tell if it simplifies further than this? I feel like it might but am not sure where. Thanks again for your help!
zzinfinity said:I don't have any idea what is meant by '...'. That's why I just multiplied it through. But I guess its not that simple, huh? :)
Basically I know the next to the last term is log2a+?(2a+?+1). So that means to me that 2b=2a+?
Am I thinking about that correctly? Even if I am, I'm still not really sure where to go from there. Is there a relationship between b and a I'm not seeing? I'm not sure how to write it out explicitly. I feel like I'm getting close though!
There are many online resources available to help with homework, such as educational websites, video tutorials, and online forums. You can also ask your teacher or classmates for additional help.
If you are struggling with a specific concept in your homework, try breaking it down into smaller parts and focusing on one at a time. You can also try researching the concept online or asking a classmate or teacher for clarification.
Yes, it is absolutely okay to ask for help with your homework. In fact, seeking help can often lead to a better understanding of the material and improved academic performance.
To effectively manage your time for homework, try creating a schedule and setting specific goals for each study session. It can also be helpful to eliminate distractions and find a quiet, comfortable study space.
If you cannot find the answer to a homework question, don't panic. Take a break and come back to the question later, or try reaching out to your teacher or classmates for assistance. Remember to always try your best and don't be afraid to ask for help when needed.